Question

抱歉我的英文。我尝试使用post和multipart / form-data将图像发送到服务器。我花了很多次，尝试修复我的代码，但都无济于事。这是我需要作为图像发送的示例：

----WebKitFormBoundaryE19zNvXGzXaLvS5C
Content-Disposition: form-data; name="image"; filename="imageName.jpeg"
Content-Type: image/jpeg

----WebKitFormBoundaryE19zNvXGzXaLvS5C

这是我的第一个版本：

public static String executeHttpLoadImage(String url, String nameValueF, String paramValueF, String nameValueS, String paramValueS,
                                                File file, String fileName) throws Exception {
        BufferedReader in = null;
        try {
            String BOUNDARY= "----WebKitFormBoundaryE19zNvXGzXaLvS5C";

            HttpClient client = createHttpClient();

            HttpPost request = new HttpPost(); //post
            request.setURI(new URI(url));

            request.setHeader("Content-Type", "multipart/form-data; boundary="+BOUNDARY); //set header

            request.setHeader(nameValueF, paramValueF);               //set header
            request.setHeader(nameValueS, paramValueS);               //set header

            //set multipart
            MultipartEntity entity = new MultipartEntity(HttpMultipartMode.BROWSER_COMPATIBLE,BOUNDARY,Charset.defaultCharset());
            try {

                entity.addPart("file01", new FileBody(file));
                request.addHeader("Accept-Encoding", "gzip, deflate");

            } catch(Exception e) {
                Log.e("error", e.toString());
            }

            request.setHeader("Content-Type", "multipart/form-data; boundary="+BOUNDARY);
            request.setEntity(entity);


            //set multipart

            HttpResponse response = client.execute(request);
            in = new BufferedReader(new InputStreamReader(response.getEntity().getContent()));

            StringBuffer sb = new StringBuffer("");
            String line = "";
            String NL = System.getProperty("line.separator");
            while ((line = in.readLine()) != null) {
                sb.append(line + NL);
            }
            in.close();

            String result = sb.toString();
            return result;
        } finally {
            if (in != null) {
                try {
                    in.close();
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
        }
    }

我的第二个版本：

public static String executeHttpLoadImage(String url, String nameValueF, String paramValueF, String nameValueS, String paramValueS,
                                                File file, String fileName) throws Exception {
        BufferedReader in = null;
        try {
            String BOUNDARY= "----WebKitFormBoundaryE19zNvXGzXaLvS5C";

            HttpClient client = createHttpClient();

            HttpPost request = new HttpPost(); //post
            request.setURI(new URI(url));

            request.setHeader("Content-Type", "form-data; name=image; filename=imageName.jpeg"); //set header

            request.setHeader(nameValueF, paramValueF);               //set header
            request.setHeader(nameValueS, paramValueS);               //set header

            //set multipart
            MultipartEntity entity = new MultipartEntity(HttpMultipartMode.BROWSER_COMPATIBLE,BOUNDARY,Charset.defaultCharset());
            try {

                entity.addPart("file01", new FileBody(file));

            } catch(Exception e) {
                Log.e("error", e.toString());
            }


            //set multipart

            HttpResponse response = client.execute(request);
            in = new BufferedReader(new InputStreamReader(response.getEntity().getContent()));

            StringBuffer sb = new StringBuffer("");
            String line = "";
            String NL = System.getProperty("line.separator");
            while ((line = in.readLine()) != null) {
                sb.append(line + NL);
            }
            in.close();

            String result = sb.toString();
            return result;
        } finally {
            if (in != null) {
                try {
                    in.close();
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
        }
    }

但我的所有版本都不起作用:(

UPD：

我在asynkTask中使用这个：

protected String doInBackground(String... params) {

            JSONObject json = null;


            try{
                json = new JSONObject(CustomHttpClient.executeHttpLoadImage(
                        "https://example.net", "id", "123",
                        "key", "123",
                        fileName, "image1"));

                Log.e("load image", json.toString());

            }catch(Exception e) {
                Log.e("Load image", e.toString());
            }

            return null;
        }

fileName - 我从图库中选择的文件，我会像这样：

Uri selectedImage = imageReturnedIntent.getData();

                    String[] filePathColumn = {MediaStore.Images.Media.DATA};

                    Cursor cursor = getContentResolver().query(selectedImage, filePathColumn, null, null, null);
                    cursor.moveToFirst();

                    int columnIndex = cursor.getColumnIndex(filePathColumn[0]);

                    String filePath = cursor.getString(columnIndex);
                    cursor.close();


                    try{
                        Bitmap myBitmap = decodeUri(selectedImage);

                        //set 
                        fileName = persistImage(myBitmap, "1123123");

                        //load image
                        new LoadImageToServer().execute();

                        imageRoom.setImageBitmap(myBitmap);

                    } catch(Exception e) {
                        Log.e("Image", e.toString());
                    }

//code

//method return bitmap -> file

 private File persistImage(Bitmap bitmap, String name) {
        File filesDir = context.getFilesDir();
        File imageFile = new File(filesDir, name + ".jpg");

        OutputStream os;
        try {
            os = new FileOutputStream(imageFile);
            bitmap.compress(Bitmap.CompressFormat.JPEG, 100, os);
            os.flush();
            os.close();
        } catch (Exception e) {
            Log.e("Error writing bitmap", e.toString());
        }

        return imageFile;
    }

Answer 1

我建议使用REST的库“Retrofit”。使他的http客户端不是“美丽”选项。

multipart / form-data，加载图片（android）

1 个答案: