Question

a = ['http://www.yahoo.com', 'http://www.google.net', 'gorilla', 'house.com', 'i love the net very much']
b = ['com', 'http', 'net']

result = ['http://www.yahoo.com', 'http://www.google.net', 'house.com', 'i love the net very much']

我怎样才能找到b？匹配a中的任何一个。 a是长句

我的正则表达式

for element in a:
    m = re.match("anything match in b right?")
    if m:
        print (m.group())

我不太确定在re.match里面放什么

Answer 1

a = ['http://www.yahoo.com', 'http://www.google.net', 'gorilla', 'house.com', 'i love the net very much']
b = ['com', 'http', 'net']
print list(set([i for i in a for j in b if j in i]))

编辑：

对于a中的所有b：

a = ['http://www.yahoo.com', 'http://www.google.net', 'gorilla', 'house.com', 'i love the net very much http and com too']
b = ['com', 'http', 'net']

print set(a)-set([i for i in a for j in b if j not in i])

Answer 2

不是正则表达式解决方案，但我认为您可以迭代每个字符串，并且可以使用any()进行检查。示例 -

result = []
for i in a:
    if any(x in i for x in b):
        result.append(i)

示例/演示 -

>>> a = ['http://www.yahoo.com', 'http://www.google.net', 'gorilla', 'house.com', 'i love the net very much']
>>> b = ['com', 'http', 'net']
>>>
>>> result = []
>>> for i in a:
...     if any(x in i for x in b):
...         result.append(i)
...
>>> result
['http://www.yahoo.com', 'http://www.google.net', 'house.com', 'i love the net very much']

列表理解解决方案 -

result = [i for i in a if any(x in i for x in b)]

示例/演示 -

>>> a = ['http://www.yahoo.com', 'http://www.google.net', 'gorilla', 'house.com', 'i love the net very much']
>>> b = ['com', 'http', 'net']
>>> result = [i for i in a if any(x in i for x in b)]
>>>
>>> result
['http://www.yahoo.com', 'http://www.google.net', 'house.com', 'i love the net very much']

Answer 3

使用嵌套循环，使用b。

中的每一个使用find（）函数检查每个循环

if b[x].find(a[y]) != -1:

此if语句将指示是否在b [x]中找到[y]。

匹配列表b中的任何字符串与列表a。 a是一个长句子

3 个答案: