我有以下SQL查询,其结构对我来说很奇怪:
SELECT
SUM("x1") AS "X1 col",
SUM("x2") AS "X2 col"
FROM (
SELECT DISTINCT xyz
FROM some_tables
WHERE some_cond
);
实际代码在这里:
select
sum("Req Lines") as "Requisitions Created",
sum("Approved Req") as "Requisitions Approved",
sum("Non Approved PO") as "PO Started",
sum("Approved PO") as "PO Approved",
sum("w/ Receipt") as "Receipts Completed",
sum("w/ Invoice") as "Invoices Completed"
from(
select distinct prha.Segment1 as "Req#",
pha.Segment1 as "PO#",
CASE when prha.creation_date between to_date(:myDate,'DD-MON-YY') and to_date(:myDate,'DD-MON-YY') + 7 then 'Week 1'
when prha.creation_date between to_date(:myDate,'DD-MON-YY') + 7 and to_date(:myDate,'DD-MON-YY') + 14 then 'Week 2'
when prha.creation_date between to_date(:myDate,'DD-MON-YY') + 14 and to_date(:myDate,'DD-MON-YY') + 21 then 'Week 3'
when prha.creation_date between to_date(:myDate,'DD-MON-YY') + 21 and to_date(:myDate,'DD-MON-YY') + 28 then 'Week 4'
else 'After Month 1' END as "Req_Created",
--CASE when prha.creation_date < '28-Aug-2015' then 'Week 1' else 'After Week 1' END,
1 as "Req Lines",
prha.authorization_status as "Req Status",
CASE when prha.authorization_status='APPROVED' then 1 else 0 END as "Approved Req",
CASE when pha.authorization_status='APPROVED' then 1 else 0 END as "Approved PO",
pha.authorization_status,
CASE when (pha.authorization_status = 'APPROVED' or pha.authorization_status is null) then 0 else 1 END as "Non Approved PO",
CASE when pda.quantity_delivered >=1 then 1 else 0 END as "w/ Receipt",
CASE when pda.quantity_billed >=1 then 1 else 0 END as "w/ Invoice",
prha.*,
prl.*
from po_requisition_lines_all prl,
po_requisition_headers_all prha,
po_req_distributions_all prda,
po_distributions_all pda,
po_headers_all pha
WHERE 1=1
AND prl.requisition_header_id = prha.requisition_header_id
and prl.requisition_line_id = prda.requisition_line_id
AND prda.distribution_id= pda.req_distribution_id(+)
and pha.po_header_id(+) = pda.po_header_id
--and item_description = 'Brads Test'
and prda.creation_date > to_date(:myDate,'DD-MON-YY')
and prha.org_id in (279,282,351,105,102) -- NA operating Units
)
;
我很好奇这个SQL是如何工作的,为什么你会使用这种SQL代码?
答案 0 :(得分:2)
您所展示的只是从子查询中选择聚合。
您可以查询子查询的结果,这正是您的示例中正在执行的操作。从您所显示的内容来看,以这种方式编写查询并非100%的必要,但以这种方式编写查询也没有错。我可以想到其他方法可以获得相同的结果,但在SQL方面总是不止一种方法可以让猫皮肤。