给定时间戳，得到小时的总N.秒

Question

给出一个熊猫时间戳：

> pd.Timestamp.now()
  Timestamp('2015-09-02 19:33:55.714410')

如何在一小时内获得总分钟数（或秒数，或微秒数）？ （作为总数的小数）。请注意，我并不是要求已经过了多少完整分钟（或秒或微秒）。

Answer 1

t = pd.Timestamp.now()
(t - t.normalize()).total_seconds()

修改

获取小时内的总秒数：

t = pd.Timestamp.now()
(t - t.to_period("H").start_time).total_seconds()

Answer 2

In [2]: t = Timestamp('2015-09-02 19:33:55.714410')

In [3]: t
Out[3]: Timestamp('2015-09-02 19:33:55.714410')

In [4]: t.hour
Out[4]: 19

In [6]: t.second 
Out[6]: 55

In [7]: t.microsecond
Out[7]: 714410

In [8]: t.
t.asm8              t.dayofweek         t.freqstr           t.is_quarter_end    t.isoweekday        t.nanosecond        t.resolution        t.timetz            t.today             t.tzname            t.week
t.astimezone        t.dayofyear         t.fromordinal       t.is_quarter_start  t.max               t.normalize         t.second            t.to_datetime       t.toordinal         t.utcfromtimestamp  t.weekday
t.combine           t.days_in_month     t.fromtimestamp     t.is_year_end       t.microsecond       t.now               t.strftime          t.to_datetime64     t.tz                t.utcnow            t.weekofyear
t.ctime             t.daysinmonth       t.hour              t.is_year_start     t.min               t.offset            t.strptime          t.to_julian_date    t.tz_convert        t.utcoffset         t.year
t.date              t.dst               t.is_month_end      t.isocalendar       t.minute            t.quarter           t.time              t.to_period         t.tz_localize       t.utctimetuple      
t.day               t.freq              t.is_month_start    t.isoformat         t.month             t.replace           t.timetuple         t.to_pydatetime     t.tzinfo            t.value             

Answer 3

import datetime as dt   

In [63]:
last_hour = dt.datetime(t.year , t.month , t.day , t.hour , 0 , 0)

In [67]:
(t - last_hour).total_seconds()
Out[67]:
768.129