Integer.parseInt(lineVector[i])
我正在尝试学习OOP并制作了这样的例子,但它不起作用,有人可以帮忙吗?
答案 0 :(得分:1)
这一行:
public $i = rand(0, count($names)-1);
错了。你不能在php中定义类属性。您必须在构造函数中设置它,同样,从sayTitle
方法开始,您应该使用$this->names
而不是$names
:
<?php
class titleGenerator {
public $names = array(
'Best Beer',
'Happy Burgers',
'Alexs Nachos',
'Big Sams Tacos'
);
public $i;
public function __construct() {
$this->i = rand(0, count($this->names)-1)
}
public function sayTitle() {
echo $this->names[$this->i];
}
}
$titles = new titleGenerator();
$titles->sayTitle();
?>
请注意,现在您必须使用括号实例化对象才能调用构造函数方法:
$titles = new titleGenerator();
答案 1 :(得分:0)
谢谢,它帮助了我,但是为了使代码运行正确,我做了这个: `
class titleGenerator {
public $names = array(
'Best Beer',
'Happy Burgers',
'Alexs Nachos',
'Big Sams Tacos'
);
public $i;
public function __construct() {
$this->i = rand(0, count($this->names)-1);
}
public function sayTitle() {
echo $this->names[$this->i];
}
}
$titles = new titleGenerator;
$titles->sayTitle();
&GT;`