Question

我有以下MySQL查询：

<div class="box" id="settlement1">
        <?
            $query  = "SELECT name, pub, hospital, trade FROM settlements WHERE settlementID = 1";
            $result = mysql_query($query);

            while($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
                $settlementName = $row['name'];
                $pubExists = $row['pub'];
                $hospitalExists = $row['hospital'];
                $tradeExists = $row['trade'];
            }
        ?>
        <div class="settlement-name"><? echo $settlementName; ?></div>
        <div class="settlement-contents">
            <?
                if ($hospitalExists == '1') { echo "<div class='hospital'>HOSPITAL</div>";  }
                if ($pubExists == '1') { echo "<div class='pub'>PUB</div>"; }
                if ($tradeExists == '1') { echo "<div class='trade'>TRADE</div>"; }
            ?>
        </div>
    </div>
    <div class="box" id="settlement2">
        <?
            $query  = "SELECT name, shop, hospital, trade FROM settlements WHERE settlementID = 2";
            $result = mysql_query($query);

            while($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
                $settlementName = $row['name'];
                $pubExists = $row['pub'];
                $hospitalExists = $row['hospital'];
                $tradeExists = $row['trade'];
            }
        ?>
        <div class="settlement-name"><? echo $settlementName; ?></div>
        <div class="settlement-contents">
            <?
                if ($hospitalExists == '1') { echo "<div class='hospital'>HOSPITAL</div>";  }
                if ($pubExists == '1') { echo "<div class='pub'>PUB</div>"; }
                if ($tradeExists == '1') { echo "<div class='trade'>TRADE</div>"; }
            ?>
        </div>
    </div>

现在，第一个查询工作正常，但第二个返回与第一个查询相同的结果。

所有字段在查询1到查询2中都不同

^ _ ^＆lt;（HELP！）

Answer 1

我不确定这是否是原因，但......

第一个SQL：

$query  = "SELECT name, pub, hospital, trade FROM settlements WHERE settlementID = 1";

第二

$query  = "SELECT name, shop, hospital, trade FROM settlements WHERE settlementID = 2";

第一个是酒吧，第二个是商店。但是在第二种情况下你没有在PHP中使用商店价值，只有pub（不在这个SQL字段中。

这里可能有SQL错误（数据库中没有字段）或PHP错误（检查结果数组中不存在的字段）。

Answer 2

是否可以重复使用变量 $ query 或 $ result 导致输出第一个$查询的结果或再次执行相同的查询？

一页上有多个MySQL / PHP查询，不公平！

2 个答案: