Question

我有8 UImageView个我正在添加动画。我知道我可以制作动画八次，但是我可以使用一个循环 - 也许是插值 - 吗？

这是我的动画代码：

override func viewDidLoad() {
        super.viewDidLoad()

        self.dieImage0.animationImages = [
            UIImage(named: "dicey-die1")!,
            UIImage(named: "dicey-die2")!,
            UIImage(named: "dicey-die3")!,
            UIImage(named: "dicey-die4")!,
            UIImage(named: "dicey-die5")!,
            UIImage(named: "dicey-die6")!,
            UIImage(named: "dicey-die1")!,
            UIImage(named: "dicey-die2")!,
            UIImage(named: "dicey-die3")!,
            UIImage(named: "dicey-die4")!,
            UIImage(named: "dicey-die5")!,
            UIImage(named: "dicey-die6")!,
            UIImage(named: "dicey-die1")!,
            UIImage(named: "dicey-die2")!,
            UIImage(named: "dicey-die3")!,
            UIImage(named: "dicey-die4")!,
            UIImage(named: "dicey-die5")!,
            UIImage(named: "dicey-die6")!,
            UIImage(named: "dicey-die1")!,
            UIImage(named: "dicey-die2")!,
            UIImage(named: "dicey-die3")!,
            UIImage(named: "dicey-die4")!,
            UIImage(named: "dicey-die5")!,
            UIImage(named: "dicey-die6")!
        ]

        self.dieImage0.animationRepeatCount = 1
        self.dieImage0.animationDuration = 1.0


    }

开始动画：

override func motionEnded(motion: UIEventSubtype, withEvent event: UIEvent) {

        self.dieImage0.startAnimating()  /* <======== */

        dieImage0.image = randomImages.randomDice();
        dieImage1.image = randomImages.randomDice();
        dieImage2.image = randomImages.randomDice();
        dieImage3.image = randomImages.randomDice();
        dieImage4.image = randomImages.randomDice();
        dieImage5.image = randomImages.randomDice();
        dieImage6.image = randomImages.randomDice();
        dieImage7.image = randomImages.randomDice();

        println("Motion Ended")
    }

我想为每个dieImage

制作动画

修改

我有几个UIImageView个@IBOutlet s我想制作动画。

    @IBOutlet weak var dieImage0: UIImageView!
    @IBOutlet weak var dieImage1: UIImageView!
    @IBOutlet weak var dieImage2: UIImageView!
    @IBOutlet weak var dieImage3: UIImageView!
    @IBOutlet weak var dieImage4: UIImageView!
    @IBOutlet weak var dieImage5: UIImageView!
    @IBOutlet weak var dieImage6: UIImageView!
    @IBOutlet weak var dieImage7: UIImageView!

如何循环浏览它们而不是为每个动画制作单独的动画，我已经有一个动画设置;见上文。

更新

除了两个骰子反叛之外，一切都按照惯例运作。第一个（dieImage0）始终位于1，第二个（dieImage5）根本不会做任何事情！

更新2：

这是我用于动画的代码：

let dieImages = [dieImage0, dieImage1, dieImage2, dieImage3, dieImage4, dieImage5, dieImage6, dieImage7]

for die in dieImages {
    die.animationImages = [
        UIImage(named: "dicey-die2")!,
        UIImage(named: "dicey-die6")!,
        UIImage(named: "dicey-die1")!,
        UIImage(named: "dicey-die4")!,
        UIImage(named: "dicey-die3")!,
        UIImage(named: "dicey-die5")!,
        UIImage(named: "dicey-die3")!,
        UIImage(named: "dicey-die1")!,
        UIImage(named: "dicey-die6")!,
        UIImage(named: "dicey-die3")!,
        UIImage(named: "dicey-die5")!,
        UIImage(named: "dicey-die2")!,
        UIImage(named: "dicey-die4")!
    ]

    die.animationRepeatCount = 1
    die.animationDuration = 1.0
}

现在一切正常！

Answer 1

要创建animationImages，我会这样做：

dieImage0.animationImages = (0..<4).reduce([UIImage]()) { images, _ in
    return images + (1..<7).map { UIImage(named: "dicey-die\($0)")! }
}

看起来animationImages包含24 UIImages - 4组6张图片，其中图片的名称为"dicey-dieN"，（N被数字替换在(1..<7)范围内。）

您可以创建一个包含六个图像的单个数组：

let images = (1..<7).map { UIImage(named: "dicey-die\($0)")! }

您希望这样做4次，并将所有阵列添加到一起。您可以通过调用(0..<4).reduce([UIImage]()) { ... }

来执行此操作

结果将是包含24张图像的单个数组。

然后，正如@Chris Slowik建议的那样，创建一个dieImages数组，然后遍历它们以分配随机图像：

let dieImages = [dieImage0, dieImage1, dieImage2, dieImage3, dieImage4, dieImage5, dieImage6, dieImage7]

for dieImage in dieImages {
    dieImage.image = randomImages.randomDice()
    dieImage.startAnimating()
}

您的整个motionEnded方法应该看起来像这样：

override func motionEnded(motion: UIEventSubtype, withEvent event: UIEvent) {
    let dieImages = [dieImage0, dieImage1, dieImage2, dieImage3, dieImage4, dieImage5, dieImage6, dieImage7]

    for dieImage in dieImages {
        dieImage.image = randomImages.randomDice()
        dieImage.startAnimating()
    }

}

我认为您遇到dieImage0的问题，因为您在为其分配随机图像之前开始动画。首先分配图像，然后开始设置动画。

Answer 2

是的，将图像放在一个数组中并循环遍历数组。

for var i = 0; i < dieImages.count; i++ {
    dieImages[i].startAnimating()
}

这有帮助吗？对你的意图有点困惑，但我认为这回答了你的问题

使用循环向多个UIImageViews

修改

更新

更新2：

2 个答案: