我希望能够使用每行末尾显示的删除按钮删除一行。我需要两个查询才能完全从我的数据库中删除一个人,因为我在人和函数之间有一个n-m关系。 查询如下:
delete from `Persons` where `Person ID` = '1';
我想使用实际代码中提供的删除按钮来实现这些查询,我该怎么做?
更新: 我根据克里斯蒂安·哈瑞兰(Kristian Hareland)所写的内容进行了更改,并重新加载但是这个人没有被删除,应该修改哪些内容才能使其正常工作?
showall.php:
<table>
<thead>
<tr>
<?php
// Variables
$dbhost = "localhost";
$dbuser = "root";
$dbpass = "root";
$dbname = "CISV";
$dberror1 = "Could not connect to database: ";
$dberror2 = "Could not select database: ";
$dberror3 = "Could not execute query: ";
$conn = mysql_connect($dbhost, $dbuser, $dbpass) or die ($dberror1 . mysql_error());
$select_db = mysql_select_db('CISV') or die ($dberror2 . mysql_error());
$query = "SELECT p.`Person ID`, p.`First Name`, p.`Last Name`, p.Gender, p.`Date Of Birth`, p.Email, p.`Phone Number`, c.Region, c.Country, p.`Delegation ID`
FROM Persons as p, Chapters as c
WHERE c.`Chapter ID`=p.`Chapter ID`
ORDER BY p.`Delegation ID";
$result = mysql_query($query) or die($dberror3 . mysql_error());
$row = mysql_fetch_assoc($result);
foreach ($row as $col => $value) {
echo "<th>";
echo $col;
echo "</th>";
}
?>
</tr>
</thead>
<tbody>
<?php
mysql_data_seek($result, 0);
while ($row = mysql_fetch_assoc($result)) {
?>
<tr>
<?php
foreach($row as $key => $value){
echo "<td>";
echo $value;
echo "</td>";
}
?>
<td><a href="/DeletePerson.php?id=<?php echo $result['Person ID']; ?>" class="btn btn-danger">Delete</a></td>
</tr>
<?php } ?>
DeletePerson.php:
<?php
$dbhost = "localhost";
$dbuser = "root";
$dbpass = "root";
$dbname = "CISV";
$dberror1 = "Could not connect to database: ";
$dberror2 = "Could not select database: ";
$dberror3 = "Could not execute query: ";
$conn = mysql_connect($dbhost, $dbuser, $dbpass) or die ($dberror1 . mysql_error());
$select_db = mysql_select_db('CISV') or die ($dberror2 . mysql_error());
$UserId = mysql_real_escape_string($_GET['id']);
if(isset($UserId)){
//DELETE QUERY
$Del = mysql_query("DELETE FROM `Persons` WHERE `Person ID` = '$UserId'");
if($Del){
$Flag = TRUE;
}
else{
$Flag = FALSE;
}
header("Location: /showall.php?delete=$Flag");
}
else{
die("Error");
}
答案 0 :(得分:0)
我会在这里使用JavaScript和Ajax。
答案 1 :(得分:0)
恕我直言最好的方法是创建单独的文件functions.php
<?php
//functions.php
$id = filter_this($_POST[id]);
mysql_query("delete from Persons_Functions where `Person ID` = '$id');
?>
并通过JQuery发送到那里:
function deleteuser(id){
$.post("admin_action.php", {action:'delete_user',id:id}, function(data){
if(data.trim()=="done"){
console.log("OK!");
});
}}
没有JS您可以使用HTML(只需将BUTTON更改为A):
<a href='script.php?action=delete&id=12'>DELETE</a>
和PHP:
$id = $_GET[id];//filter this value
mysqli_query($link, "DELETE FROM users WHERE ID='$id'"); //use mysqli
答案 2 :(得分:0)
我会将GET
方法用于此
<?php foreach ($results as $result): ?>
<a href="/index.php?action=delete&id=<?= $result['id']; ?>">Delete</a>
<?php endforeach; ?>
在index.php的顶部
if (isset($_GET['action']) && $_GET['action'] == 'delete') {
if (isset($_GET['id']) && intval($_GET['id']) != 0) {
$id = intval($_GET['id']);
$stmt = "delete from table where id='{$id}'";
}
}
答案 3 :(得分:0)
只需使用链接:
<?php
$UserId = mysql_real_escape_string($_GET['id']);
if(isset($UserId)){
//DELETE QUERY
mysql_query("DELETE FROM Persons WHERE Person ID = '$UserId'");
mysql_query("DELETE FROM Persons_Functions WHERE Person ID = '$UserId'");
header("Location: /showall.php?flag=deleted");
}
else{
die("Error");
}
DeletePerson.php:
int cursor = 0;
List<string> result = new List<string>();
while (cursor < parentArray.Length)
{
result.Add(String.Join("", parentArray.Skip(cursor).Take(20)));
cursor += 20;
}
string[] childArray = result.ToArray();