AsyncFileUpload在Listview Insert,Edit Itemtemplate和EmptyData Template中不起作用。
以上是我的客户端功能
function AttachmentUploadSuccessful() {
debugger;
var textError = $(".AttachmentError").text();
if (textError.length > 0) {
var text = $(".AttachmentError");
text.innerText = text.textContent = textError;
sender._onError(textError); // it will raise the OnClientUploadError event
return;
} else {
//alert(" File attachment is uploaded successfully.");
//CODE TO REMOVE FILE AND BACKGROUND COLOR OF FILE UPLOADER
$('.ModelBackgroundforCreateItem').hide();
$('.PopupPanel').hide();
var UploadControls = $('#<%= FileUpload.ClientID %> :input');
UploadControls.each(function () {
//$(this).val("");
$(this).css('background-color', '#fff');
});
//Updating Update panel by clicking button
$(".RefreshList").click();
}
}
function AttachmentUploadFailed() {
alert("An error occured while uploading File Attachment. ");
}
.aspx文件中的标记
<asp:ListView ID="ListView2" runat="server">
<EmptyDataTemplate>
<table class="fileUpload" runat="server" id="FileUploadID">
<tr>
<td>
<div style="width: 350px; overflow-x: hidden;">
<asp:AsyncFileUpload runat="server" ID="FileUpload" ThrobberID="Throbber" OnClientUploadError="AttachmentUploadFailed"
OnClientUploadComplete="AttachmentUploadSuccessful" UploaderStyle="Traditional" UploadingBackColor="" Style="display: inline-block; margin-top: 5px;"
OnUploadedComplete="FileUpload_UploadedComplete">
</asp:AsyncFileUpload>
</div>
</td>
<td style="width: 30px">
<asp:Image ID="Throbber" ImageUrl="~/Image/AttachmentLoading.gif" Style="display: None; width: 20px;" runat="server" />
<br />
</td>
</tr>
</table>
</EmptyDataTemplate>
</asp:ListView>
尝试上传文件调用客户端事件OnClientUploadError
无法理解为什么会出错。
在简单页面和内部更新面板上工作相同的文件上传,但在列表视图内,它给客户端错误。
通过以上链接问题没有得到确切的答案,请帮助我。
How to find Ajaxfileupload control inside Listview When in Editmode
答案 0 :(得分:2)
我可以在您分享的代码中看到两个问题:
var UploadControls = $('#<%= FileUpload.ClientID %> :input')
ClientIDMode
属性,因此它是Inherit
这两个问题的起源相同:您在AsyncFileUploader
内使用ListView
,因此页面中会有多个FileUpload
个ID元素。< / p>
因此,首先必须将函数声明更改为:
function AttachmentUploadSuccessful(sender, e) { // then you can get the sender
然后,要获得input
,您将使用:
var UploadControls = $(sender._inputFile);
最后,要修复第二个问题,您需要将ClientIDMode
属性更改为AutoID
,以便AsyncFileUploader
能够正确找到其引用的客户成员。< / p>