我有代码检查文件夹子文件夹中的所有文件。但是我如何才能将其更改为不仅检查子文件夹级别，还检查子文件夹的子文件夹等等？
这是我对该文件夹及其子文件夹的代码：
var fso = new ActiveXObject("Scripting.FileSystemObject");
fso = fso.getFolder(path);
var subfolders = new Object();
subfolders = fso.SubFolders;
var oEnumerator = new Enumerator(subfolders);
for (;!oEnumerator.atEnd(); oEnumerator.moveNext())
{
var itemsFolder = oEnumerator.item().Files;
var oEnumerator2 = new Enumerator(itemsFolder);
var clientFileName = null;
for(;!oEnumerator2.atEnd(); oEnumerator2.moveNext())
{
var item = oEnumerator2.item();
var itemName = item.Name;
var checkFile = itemName.substring(itemName.length - 3);
if(checkFile == ".ac")
{
var clientFileName = itemName;
break;
}
}
}
在每个级别的子文件夹上，我需要检查所有文件是否可以找到.ac文件。
答案 0 :(得分：0)
我在评论中提到的解决方案看起来像这样（我对ActiveX不太了解，因此有很多评论，所以希望你可以轻松纠正任何错误）：
//this is the function that looks for the file inside a folder.
//if it's not there, it looks in every sub-folder by calling itself
function getClientFileName(folder) {
//get all the files in this folder
var files = folder.Files;
//create an enumerator to check all the files
var enumerator = new Enumerator(files);
for(;!enumerator.atEnd(); enumerator.moveNext()) {
//get the file name we're about to check
var file = enumerator.item().Name;
//if the file name is too short skip this one
if (file.length<3) continue;
//check if this file's name matches, if it does, return it
if (file.substring(file.length - 3)==".ac") return file;
}
//if we finished this loop, then the file was not inside the folder
//so we check all the sub folders
var subFolders = folder.SubFolders;
//create an enumerator to check all sub folders
enumerator = new Enumerator(subFolders);
for(;!enumerator.atEnd(); enumerator.moveNext()) {
//get the sub folder we're about to check
var subFolder = enumerator.item();
//try to find the file in this sub folder
var fileName = getClientFileName(subFolder);
//if it was inside the sub folder, return it right away
if (fileName!=null) return fileName;
}
//if we get this far, we did not find the file in this folder
return null;
}
然后你会像这样调用这个函数：
var theFileYouAreLookingFor = getClientFileName(theFolderYouWantToStartLookingIn);
再一次，要注意上面的代码：我没有测试它，也不了解ActiveX，我只是拿了你的代码并改了它，所以它应该查看所有的子文件夹。
答案 1 :(得分：0)
你想要的是一个递归函数。这是一个简单的递归函数，它通过提供的路径中的每个文件进行迭代，然后进行递归调用以通过每个子文件夹文件进行迭代。对于遇到的每个文件，此函数调用提供的回调（您可以在其中执行任何处理逻辑）。
功能：
function iterateFiles(path, recursive, actionPerFileCallback){
var fso = new ActiveXObject("Scripting.FileSystemObject");
//Get current folder
folderObj = fso.GetFolder(path);
//Iterate thru files in thisFolder
for(var fileEnum = new Enumerator(folderObj.Files); !fileEnum.atEnd(); fileEnum.moveNext()){
//Get current file
var fileObj = fso.GetFile(fileEnum.item());
//Invoke provided perFile callback and pass the current file object
actionPerFileCallback(fileObj);
}
//Recurse thru subfolders
if(recursive){
//Step into each sub folder
for(var subFolderEnum = new Enumerator(folderObj.SubFolders); !subFolderEnum.atEnd(); subFolderEnum.moveNext()){
var subFolderObj = fso.GetFolder(subFolderEnum.item());
//Make recursive call
iterateFiles(subFolderObj.Path, true, actionPerFileCallback);
}
}
};
用法（这里我传入一个匿名函数，为每个文件调用）：
iterateFiles(pathToFolder, true, function(fileObj){
Wscript.Echo("File Name: " + fileObj.Name);
};
现在..这是一个非常基本的例子。下面是一个类似功能的更复杂的实现。在这个函数中，我们可以像以前一样递归地遍历每个文件。但是，现在调用者可以向函数提供“调用上下文”，该调用上下文又被传递回回调。这可能很强大，因为现在调用者可以使用它自己的闭包中的先前信息。另外，我为调用者提供了在每个递归级别更新调用上下文的机会。在设计此函数时，为了满足我的特定需求，有必要提供检查每个回调函数是否成功的选项。所以，你会在这个函数中看到对它的检查。我还包括为遇到的每个文件夹执行回调的选项。
更复杂的功能：
function iterateFiles(path, recursive, actionPerFileCallback, actionPerFolderCallback, useFnReturnValue, callingContext, updateContextFn){
var fso = new ActiveXObject("Scripting.FileSystemObject");
//If 'useFnReturnValue' is true, then iterateFiles() should return false IFF a callback fails.
//This function simply tests that case.
var failOnCallbackResult = function(cbResult){
return !cbResult && useFnReturnValue;
}
//Context that is passed to each callback
var context = {};
//Handle inputs
if(callingContext != null){
context.callingContext = callingContext;
}
//Get current folder
context.folderObj = fso.GetFolder(path);
//Do actionPerFolder callback if provided
if(actionPerFolderCallback != null){
var cbResult = Boolean(actionPerFolderCallback(context));
if (failOnCallbackResult(cbResult)){
return false;
}
}
//Iterate thru files in thisFolder
for(var fileEnum = new Enumerator(context.folderObj.Files); !fileEnum.atEnd(); fileEnum.moveNext()){
//Get current file
context.fileObj = fso.GetFile(fileEnum.item());
//Invoke provided perFile callback function with current context
var cbResult = Boolean(actionPerFileCallback(context));
if (failOnCallbackResult(cbResult)){
return false;
}
}
//Recurse thru subfolders
if(recursive){
//Step into sub folder
for(var subFolderEnum = new Enumerator(context.folderObj.SubFolders); !subFolderEnum.atEnd(); subFolderEnum.moveNext()){
var subFolderObj = fso.GetFolder(subFolderEnum.item());
//New calling context that will be passed into recursive call
var newCallingContext;
//Provide caller a chance to update the calling context with the new subfolder before making the recursive call
if(updateContextFn != null){
newCallingContext = updateContextFn(subFolderObj, callingContext);
}
//Make recursive call
var cbResult = iterateFiles(subFolderObj.Path, true, actionPerFileCallback, actionPerFolderCallback, useFnReturnValue, newCallingContext, updateContextFn);
if (failOnCallbackResult(cbResult)){
return false;
}
}
}
return true; //if we made it here, then all callbacks were successful
};
用法：
//Note: The 'lib' object used below is just a utility library I'm using.
function copyFolder(fromPath, toPath, overwrite, recursive){
var actionPerFileCallback = function(context){
var destinationFolder = context.callingContext.toPath;
var destinationPath = lib.buildPath([context.callingContext.toPath, context.fileObj.Name]);
lib.createFolderIfDoesNotExist(destinationFolder);
return copyFile(context.fileObj.Path, destinationPath, context.callingContext.overwrite);
};
var actionPerFolderCallback = function(context){
var destinationFolder = context.callingContext.toPath;
return lib.createFolderIfDoesNotExist(destinationFolder);
};
var callingContext = {
fromPath : fromPath,
toPath : lib.buildPath([toPath, fso.GetFolder(fromPath).Name]), //include folder in copy
overwrite : overwrite,
recursive : recursive
};
var updateContextFn = function(currentFolderObj, previousCallingContext){
return {
fromPath : currentFolderObj.Path,
toPath : lib.buildPath([previousCallingContext.toPath, currentFolderObj.Name]),
overwrite : previousCallingContext.overwrite,
recursive : previousCallingContext.recursive
}
}
return iterateFiles(fromPath, recursive, actionPerFileCallback, null, true, callingContext, updateContextFn);
};
我知道这个问题已经过时了，但我偶然发现了它，希望我的回答可以帮助别人！