Question

我是PHP新手并尝试生成以下json输出：

{
  "contacts": [
    {
      "id": "1",
      "name": "John Bob",
      "email": "john@bob.com"
    },
    {
      "id": "2",
      "name": "Johnny Mac",
      "email": "johnny@mac.com"
    },
      .....
  ]
}

我有以下PHP代码：

$final = array();
foreach ($contacts as $contact)
{
  .....
  $final[] = array(
      'id'           => (string)$id,
      'name'         => $name,
      'email'        => $email
    );
}
header('Content-Type: application/json; charset=UTF-8');
echo json_encode($final, JSON_PRETTY_PRINT);

然而，这输出：

[
  {
    "id": "1",
    "name": "John Bob",
    "email": "john@bob.com"
  },
  {
    "id": "2",
    "name": "Johnny Mac",
    "email": "johnny@mac.com"
  },
]

我阅读this tutorial并将$final[]更改为$final['contacts']，但仍然无法生成所需的json文件。

Answer 1

 foreach ($contacts as $contact)
 {
   .....
   $final['contacts'][] = array(
             array( //insert all your array in contacts
               'id'       => (string)$id,
               'name'     => $name,
               'email'    => $email
    );
 }

Answer 2

或者：

$final['contacts'][] = array(..);

或：

$contacts_output = array();
foreach ($contacts as $contact) {
    $contacts_output[] = array(..);
}
$final = array('contacts' => $contacts_output);
echo json_encode($final, JSON_PRETTY_PRINT);

Answer 3

试试这个：

$final = array();
$final['contacts'] = array();
foreach ($contacts as $contact)
{
  .........
  $final['contacts'][] = array( 
    'id'       => (string)$id,
    'name'     => $name,
    'email'    => $email 
  );
}

Answer 4

$final = array('contacts'=>[]);

foreach ($contacts as $contact)
{
    $final['contacts'] []=
            array( //insert all your array in contacts
                'id'       => (string)$id,
                'name'     => $name,
                'email'    => $email 
            );
}

PHP中的对象数组

4 个答案: