如何比较" peewee.DateField"使用" datatime.date"?

时间:2015-09-02 07:26:26

标签: python python-2.7 datetime peewee datefield

我编写了以下程序来获取我的数据库的一些行,其中包含有关22-Jan-1963之后出生的用户的信息:

import datetime as dt
import peewee as pw
db = pw.SqliteDatabase('people.db')

class Person(pw.Model):
    name = pw.CharField()
    birthday = pw.DateField(formats=['%d-%b-%Y'])

    class Meta:
        database = db # This model uses the "people.db" database.

db.create_tables([Person])

bob = Person(name = 'Bob', birthday = '21-Jan-1960')
james = Person(name = 'James', birthday = '22-Jan-1965')
steve = Person(name = 'Steve', birthday = '20-Jan-1970')
alex = Person(name = 'Alex', birthday = '18-Jan-1975')
bob.save()
james.save()
steve.save()
alex.save()

for item in Person.select().where(Person.birthday > dt.date(1963,1,22)):
    print item.name,item.birthday, item.birthday > dt.date(1963,1,22)

但是当我运行它时,输出不是我预期的(我希望输出中有 James,Steve和Alex ):

>>> ================================ RESTART ================================
>>> 
Bob 1960-01-21 False
James 1965-01-22 True
Steve 1970-01-20 True
>>> 

好吧,我在dt.date(1963,1,22)方法中将"22-Jan-1963"替换为where(),现在结果为:

>>> ================================ RESTART ================================
>>> 
James 1965-01-22 True
>>> 

如上所述,它仍然不正确。

我该怎么办?

2 个答案:

答案 0 :(得分:3)

我绝对不认识PeeWee,但鉴于Sqlite没有原生日期时间格式(它将其模仿为字符串),您可能想尝试将日期格式更改为"%Y-%m-%d";这将自动正确地作为字符串排序,这可能适用于Sqlite。

答案 1 :(得分:1)

documentation之后,我建议

other = dt.date(1963, 1, 22)
Person.select().where(
    Person.birthday.year >= other.year
).where(
    Person.birthday.year > other.year
    | Person.birthday.month >= other.month
).where(
    Person.birthday.year > other.year
    | Person.birthday.month > other.month
    | Person.birthday.day > other.day
)

是的,这很啰嗦......