我的表格包含以下栏目：
[name_of_pos] varchar,
[date_from] datetime,
[date_to] datetime
以下是我的示例数据：
name_of_pos date_from date_to
----------------------------------------------------------------
Asystent 2015-08-26 08:57:49.000 2015-09-04 08:57:49.000
Biuro 2015-09-01 08:53:32.000 2015-09-01 08:53:32.000
Biuro 2015-09-02 09:00:41.000 2015-09-02 09:00:41.000
Biuro 2015-09-03 11:46:03.000 2015-09-03 11:46:03.000
Biuro 2015-09-10 09:02:11.000 2015-09-15 09:02:11.000
Koordynator 2015-09-01 09:04:06.000 2015-09-01 09:04:06.000
Projektant 2015-08-31 08:59:46.000 2015-09-01 08:59:46.000
Projektant 2015-09-02 08:00:54.000 2015-09-02 08:00:54.000
Projektant 2015-09-14 12:34:50.000 2015-09-14 12:34:50.000
我想要返回的是每个date_from的日期范围（date_to到最大name_of_pos），但仅限于日期值是连续的（时间部分是不重要，结果可以忽略。
所需的输出是：
name_of_pos date_from date_to
------------------------------------
Asystent 2015-08-26 2015-09-04
Biuro 2015-09-01 2015-09-03
Biuro 2015-09-10 2015-09-15
Koordynator 2015-09-01 2015-09-01
Projektant 2015-08-31 2015-09-02
Projektant 2015-09-14 2015-09-14
我尝试使用与此问题类似的解决方案：
How do I group on continuous ranges
但由于我有两个日期时间列，所以没有运气。
答案 0 :(得分：1)
这是一个解决方案，使用cte迭代行（在订购后）并检查分组前的连续几天：
-- dummy table
CREATE TABLE #TableA
(
[name_of_pos] VARCHAR(11) ,
[date_from] DATETIME ,
[date_to] DATETIME
);
-- insert dummy data
INSERT INTO #TableA
( [name_of_pos], [date_from], [date_to] )
VALUES ( 'Asystent', '2015-08-26 08:57:49', '2015-09-04 08:57:49' ),
( 'Biuro', '2015-09-01 08:53:32', '2015-09-01 08:53:32' ),
( 'Biuro', '2015-09-02 09:00:41', '2015-09-02 09:00:41' ),
( 'Biuro', '2015-09-03 11:46:03', '2015-09-03 11:46:03' ),
( 'Biuro', '2015-09-10 09:02:11', '2015-09-15 09:02:11' ),
( 'Koordynator', '2015-09-01 09:04:06', '2015-09-01 09:04:06' ),
( 'Projektant', '2015-08-31 08:59:46', '2015-09-01 08:59:46' ),
( 'Projektant', '2015-09-02 08:00:54', '2015-09-02 08:00:54' ),
( 'Projektant', '2015-09-14 12:34:50', '2015-09-14 12:34:50' );
-- new temp table used to add row numbers for data order
SELECT name_of_pos, CAST(date_from AS DATE) date_from, CAST(date_to AS DATE) date_to,
ROW_NUMBER() OVER ( ORDER BY name_of_pos, date_from ) rn
INTO #temp
FROM #TableA
-- GroupingColumn in cte used to identify and group consecutive dates
;WITH cte
AS ( SELECT name_of_pos ,
date_from ,
date_to ,
1 AS GroupingColumn ,
rn
FROM #temp
WHERE rn = 1
UNION ALL
SELECT t2.name_of_pos ,
t2.date_from ,
t2.date_to ,
CASE WHEN t2.date_from = DATEADD(day, 1, cte.date_to)
AND cte.name_of_pos = t2.name_of_pos
THEN cte.GroupingColumn
ELSE cte.GroupingColumn + 1
END AS GroupingColumn ,
t2.rn
FROM #temp t2
INNER JOIN cte ON t2.rn = cte.rn + 1
)
SELECT name_of_pos, MIN(date_from) AS date_from, MAX(date_to) AS date_to
FROM cte
GROUP BY name_of_pos, GroupingColumn
DROP TABLE #temp
DROP TABLE #TableA
产生您想要的输出：
name_of_pos date_from date_to
Asystent 2015-08-26 2015-09-04
Biuro 2015-09-01 2015-09-03
Biuro 2015-09-10 2015-09-15
Koordynator 2015-09-01 2015-09-01
Projektant 2015-08-31 2015-09-02
Projektant 2015-09-14 2015-09-14
答案 1 :(得分：1)
这是一个缺口和岛屿问题。这是调整official 完成它的方法，这将作为解决方案进行检查：
;with
cte as (
SELECT *,
dateadd( day,
- (ROW_NUMBER() OVER (
partition by name_of_pos
ORDER BY t.date_from
) + -- here starts tuned part --
isnull(
sum( datediff(day, date_from, date_to ) ) OVER (
partition by name_of_pos
ORDER BY t.date_from
ROWS BETWEEN UNBOUNDED PRECEDING and 1 PRECEDING
) ,0) -- here ends tuned part --
),
date_from
) as Grp
FROM t
)
SELECT name_of_pos
,min(date_from) AS date_from
,max(date_to) AS date_to
FROM cte
GROUP BY name_of_pos, Grp
ORDER BY name_of_pos, date_from
此处tested on sqlfiddle（包含一些不同的示例数据）。
答案 2 :(得分：0)
您可以使用<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:orientation="vertical"
android:padding="10dp" >
<LinearLayout
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:orientation="horizontal"
android:padding="10dp" >
<Button
android:id="@+id/col1"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_weight="1"
android:background="#F8BBD0" />
<Button
android:id="@+id/col2"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_marginLeft="20dp"
android:layout_weight="1"
android:background="#FFCCBC" />
<Button
android:id="@+id/col3"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_marginLeft="20dp"
android:layout_weight="1"
android:background="#E1BEE7" />
</LinearLayout>
<LinearLayout
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:padding="10dp" >
<Button
android:id="@+id/col4"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_weight="1"
android:background="#BBDEFB" />
<Button
android:id="@+id/col5"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_marginLeft="20dp"
android:layout_weight="1"
android:background="#C8E6C9" />
<Button
android:id="@+id/col6"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_marginLeft="20dp"
android:layout_weight="1"
android:background="#FFF9C4" />
</LinearLayout>
，但根据我的经验，最快的方法是在循环中使用更新：
cte答案 3 :(得分：-2)
尝试一次：
SELECT name_of_pos, date_from,date_to
FROM table
ORDER BY
name_of_pos asc, date_from desc;