我正在研究VB程序,相当基本(没有双关语),我需要将基本整数转换为罗马数字。我的转换部分与我的Select Case完美配合。我还需要添加验证输入,因此如果输入的数字无效,则文本框会显示。 1到10之间的任何数字都应该能够单击转换按钮。目前,我在1到10之间输入的任何数字都会立即显示,“该数字无效。”
这是我当前的代码,但失败了:
Public Class Form1
Private Sub Form1_Load(sender As Object, e As EventArgs) Handles MyBase.Load
End Sub
Private Sub lblRomanNum_Click(sender As Object, e As EventArgs)
End Sub
Private Sub txtBox1_TextChanged(sender As Object, e As EventArgs) Handles txtBox1.TextChanged
Dim intNum As Integer
If intNum < 1 Or intNum > 10 Then
txtBox1.Text = "That number is invalid."
'ElseIf intNum > 10 Then
'txtBox1.Text = "That number is invalid"
End If
End Sub
Private Sub txtBox2_TextChanged(sender As Object, e As EventArgs) Handles txtBox2.TextChanged
End Sub
Private Sub btnConvert_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnConvert.Click
Select CInt(txtBox1.Text)
Case 1 ' numerical 1
txtBox2.Text = "I"
Case 2 ' numerical 2
txtBox2.Text = "II"
Case 3 ' numerical 3
txtBox2.Text = "III"
Case 4 ' numerical 4
txtBox2.Text = "IV"
Case 5 ' numerical 5
txtBox2.Text = "V"
Case 6 ' numerical 6
txtBox2.Text = "VI"
Case 7 ' numerical 7
txtBox2.Text = "VII"
Case 8 ' numerical 8
txtBox2.Text = "VIII"
Case 9 ' numerical 9
txtBox2.Text = "IX"
Case 10 ' numerical 10
txtBox2.Text = "X"
'Case Else
'If a user enters an invalid value, this message is displayed and no conversion is attempted, according to instructions.
'txtBox2.Text = "That value is invalid."
End Select
End Sub
Private Sub btnExit_Click(sender As Object, e As EventArgs) Handles btnExit.Click
Me.Close()
End Sub
Private Sub lblRomanNum_Click_1(sender As Object, e As EventArgs)
End Sub
End Class
任何小于1的intNum都应显示无效消息。
任何大于10的intNum都应显示无效消息。
如果我正在阅读目前正确的内容,这应该可以使用,并允许我输入1到10之间的数字,而不会显示无效消息。我在这里错过了什么吗?
答案 0 :(得分:1)
尝试使用括号和'或'
1. Dim intNum As Integer
2. If (intNum < 1) or (intNum > 10) Then
3. txtBox1.Text = "That number is invalid."
4. End If
答案 1 :(得分:0)
您的代码在Visual Studio 2013中使用.NET Framework 4.5.1非常适合我。尝试删除整个块并重新键入代码。 或者你也可以尝试这个代码
If intNum < 1 OrElse intNum > 10 Then
TextBox1.Text = "That number is invalid."
End If
答案 2 :(得分:0)
需要添加......
Integer.TryParse(txtBox1.Text, i)
...直接在我的变量声明下。