Question

我正在编写一个脚本来检查文件列表中的图像序列。到目前为止，它运行得相当好，但由于某种原因，它总是跳过每个新序列的第一个文件。到目前为止，这是我的代码：

import os, re
filelist = ["A01B02_0123_A333.01234321.ari", "A01B02_0123_A333.01234322.ari", "A01B02_0123_A333.01234323.ari", "A01B02_0123_A333.01234324.ari", "A01B02_0123_A333.01234325.ari", "A01B02_0123_A333.01234326.ari", "A01B02_0123_A333.01234327.ari", "A01B02_0123_A333.01234328.ari", "A01B02_0123_A333.01234329.ari", "A01B02_0123_A333.01234330.ari", "A01B02_0123_A333.01234331.ari", "A02B03_0123_A444.0052.ari", "bus_v01.1001.tif", "bus_v01.1002.tif", "bus_v01.1003.tif", "bus_v02.1001.tif", "bus_v02.1002.tif", "bus_v02.1003.tif", "elementA_1001.jpg", "elementA_1002.jpg", "elementA_1003.jpg", "elementB_1001.jpg", "elementB_1002.jpg", "elementB_1003.jpg"]

def digitgroups(file):
    padding_expr = re.compile("\d+")
    lastfile = ""
    sequence_index = 0

    for file in filelist:

        if file.endswith((".dpx", ".ari", ".jpg", ".tif")):
            match = re.findall(padding_expr, file)[::-1]
            lastmatch = re.findall(padding_expr, lastfile)[::-1]

            if len(match) == len (lastmatch) and file != lastfile:

                for i in range (0, len(match)):
                    digit_difference = int(lastmatch[i])-int(match[i])

                    if not (digit_difference) == 0:

                        if digit_difference == -1 or digit_difference == 1 and os.path.splitext(file)[-1] is os.path.splitext(l)[-1]:
                            print file, "a is part of sequence {0}".format(sequence_index)
                        elif digit_difference < -1 or digit_difference > 1:
                            sequence_index += 1

                        break

            lastfile = file

digitgroups(filelist)

Answer 1

除了评论中提到的所有内容外，循环依赖于lastfile不为空。

第一遍：

if len(match) == len (lastmatch) and file is not lastfile:

在第一次传递时不会成立，因为lastfile设置为""而len(lastmatch)将设为0。

此外，您正在传递list，然后在函数中调用file。下面的解决方案对我有用（EDITED，更完整的解决方案）：

import os, re
mylist = ["A01B02_0123_A333.01234321.ari", "A01B02_0123_A333.01234322.ari", "A01B02_0123_A333.01234323.ari", "A01B02_0123_A333.01234324.ari", "A01B02_0123_A333.01234325.ari", "A01B02_0123_A333.01234326.ari", "A01B02_0123_A333.01234327.ari", "A01B02_0123_A333.01234328.ari", "A01B02_0123_A333.01234329.ari", "A01B02_0123_A333.01234330.ari", "A01B02_0123_A333.01234331.ari", "A02B03_0123_A444.0052.ari", "bus_v01.1001.tif", "bus_v01.1002.tif", "bus_v01.1003.tif", "bus_v02.1001.tif", "bus_v02.1002.tif", "bus_v02.1003.tif", "elementA_1001.jpg", "elementA_1002.jpg", "elementA_1003.jpg", "elementB_1001.jpg", "elementB_1002.jpg", "elementB_1003.jpg"]

def digitgroups(files):
    padding_expr = re.compile("\d+")
    lastfile = ""
    sequence_index = 0

    for f in files:
        if f.endswith((".dpx", ".ari", ".jpg", ".tif")):
            match = re.findall(padding_expr, f)[::-1]
            lastmatch = re.findall(padding_expr, lastfile)[::-1]

            if len(match) == len(lastmatch) and f is not lastfile:
                for i in range (0, len(match)):
                    digit_difference = int(lastmatch[i])-int(match[i])
                    if not digit_difference == 0:
                        if digit_difference == -1 or digit_difference == 1 and os.path.splitext(f)[-1] is os.path.splitext(l)[-1]:
                            print(f, "a is part of sequence {0}".format(sequence_index))
                        elif digit_difference < -1 or digit_difference > 1:
                            sequence_index += 1

                        break
            else:
                print(f, "a is part of sequence {0}".format(sequence_index))
            lastfile = f

digitgroups(mylist)

注意lastfile = files.pop(0)。这将从files列表中获取第一个元素。

python图像序列循环问题

1 个答案: