我在我的vps:http://permadi.com/2010/10/html5-saving-canvas-image-data-using-php-and-ajax/
上遵循了本教程testSave.php
<?php
if (isset($GLOBALS["HTTP_RAW_POST_DATA"]))
{
// Get the data
$imageData=$GLOBALS['HTTP_RAW_POST_DATA'];
// Remove the headers (data:,) part.
// A real application should use them according to needs such as to check image type
$filteredData=substr($imageData, strpos($imageData, ",")+1);
// Need to decode before saving since the data we received is already base64 encoded
$unencodedData=base64_decode($filteredData);
//echo "unencodedData".$unencodedData;
$randnum = rand(1111111111,9999999999);
// Save file. This example uses a hard coded filename for testing,
// but a real application can specify filename in POST variable
$tmpfname = tempnam("http://123.xx.xx.xx/test/tmp/", "FOO");
$fp = fopen(http://123.xx.xx.xx/test/test . uniqid() .".png","wb");
fwrite( $fp, $unencodedData);
fclose( $fp );
}
?>
JS
function saveViaAJAX()
{
var testCanvas = document.getElementById("testCanvas");
var canvasData = testCanvas.toDataURL("image/png");
var postData = "canvasData="+canvasData;
var debugConsole= document.getElementById("debugConsole");
debugConsole.value=canvasData;
//alert("canvasData ="+canvasData );
var ajax = new XMLHttpRequest();
ajax.open("POST",'testSave.php',true);
ajax.setRequestHeader('Content-Type', 'canvas/upload');
//ajax.setRequestHeader('Content-TypeLength', postData.length);
ajax.onreadystatechange=function()
{
if (ajax.readyState == 4)
{
//alert(ajax.responseText);
// Write out the filename.
document.getElementById("debugFilenameConsole").innerHTML="Saved as<br><a target='_blank' href='"+ajax.responseText+"'>"+ajax.responseText+"</a><br>Reload this page to generate new image or click the filename to open the image file.";
}
}
ajax.send(postData);
}
问题是当用户点击“通过ajax发送”时,服务器目录(http://prntscr.com/8bhmxa)中没有发送/生成的图像。这是结果:http://prntscr.com/8bhi62并且目录中的所有内容都保持不变。
在“保存为”
下生成的图像链接应该会发生什么任何解决方案?
P.S。 无论如何用em回显图像链接?