Question

当我尝试运行单元测试时出现奇怪的异常。这是堆栈跟踪：

javax.persistence.PersistenceException: [PersistenceUnit: testPU] Unable to build Hibernate SessionFactory
    at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl.persistenceException(EntityManagerFactoryBuilderImpl.java:1249)
    at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl.access$600(EntityManagerFactoryBuilderImpl.java:120)
     ... more
Caused by: org.hibernate.MappingException: Could not instantiate persister org.hibernate.persister.entity.SingleTableEntityPersister
    at org.hibernate.persister.internal.PersisterFactoryImpl.create(PersisterFactoryImpl.java:174)
    at org.hibernate.persister.internal.PersisterFactoryImpl.createEntityPersister(PersisterFactoryImpl.java:135)
    at org.hibernate.internal.SessionFactoryImpl.<init>(SessionFactoryImpl.java:401)
    at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1859)
    at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl$4.perform(EntityManagerFactoryBuilderImpl.java:857)
    ... 39 more
Caused by: java.lang.ClassCastException: org.hibernate.type.SerializableType cannot be cast to org.hibernate.type.VersionType
    at org.hibernate.tuple.PropertyFactory.buildVersionProperty(PropertyFactory.java:181)
    at org.hibernate.tuple.entity.EntityMetamodel.<init>(EntityMetamodel.java:218)
    at org.hibernate.persister.entity.AbstractEntityPersister.<init>(AbstractEntityPersister.java:520)
    at org.hibernate.persister.entity.SingleTableEntityPersister.<init>(SingleTableEntityPersister.java:148)
    at sun.reflect.GeneratedConstructorAccessor29.newInstance(Unknown Source)
    at sun.reflect.DelegatingConstructorAccessorImpl.newInstance(DelegatingConstructorAccessorImpl.java:45)
    at java.lang.reflect.Constructor.newInstance(Constructor.java:422)
    at org.hibernate.persister.internal.PersisterFactoryImpl.create(PersisterFactoryImpl.java:163)
    ... 43 more

以下是我正在使用的库和框架：

JPA 2.0
org.hibernate作为：休眠-的EntityManager：4.3.5.Final
com.h2database：H2：1.4.188
的junit：junit的：4.11
Intellij IDE（我刚刚在这里运行测试）
org.hibernate作为：休眠-envers：4.3.5.Final

好吧，我打赌任何看过这个的人都希望看到persistense.xml文件，所以这里是：

<?xml version="1.0" encoding="UTF-8"?>
<persistence xmlns="http://java.sun.com/xml/ns/persistence" version="2.0">
    <persistence-unit name="testPU" transaction-type="RESOURCE_LOCAL">
        <provider>org.hibernate.jpa.HibernatePersistenceProvider</provider>
        <exclude-unlisted-classes>true</exclude-unlisted-classes>

这里有很多课程，所以我将它们删除以保持可读性

        <properties>
            <property name="javax.persistence.jdbc.driver" value="org.h2.Driver" />
            <property name="javax.persistence.jdbc.url" value="jdbc:h2:mem:test;MODE=PostgreSQL;INIT=create schema if not exists test;DB_CLOSE_DELAY=-1" />
            <property name="javax.persistence.jdbc.user" value="sa" />
            <property name="javax.persistence.jdbc.password" value="" />
            <property name="hbm2ddl.auto" value="create" />
            <property name="hibernate.dialect" value="org.hibernate.dialect.PostgreSQL9Dialect"/>
            <property name="hibernate.show_sql" value="false"/>
        </properties>
    </persistence-unit>
</persistence>

单元测试是基本的。它只是通过值找到记录。这是代码：

@Test
  public void testFindByNaturalKeyReturnsBusinessUnit() {
    final BusinessUnit businessUnit = mock(BusinessUnit.class);
    assertThat(businessUnitDao.findByNaturalKey(businessUnit.getNaturalKey()).getId(), is(businessUnit.getId()));
  }

最后，实体真的很复杂。我不确定发布代码是否会有所帮助。我想在实体中存在一个错误的关系，所以我正在研究它。

Answer 1

好的，有一个答案。实体类在某些字段中使用了JodaTime。这要求persistence.xml文件设置一些其他属性。

JodaTime字段的示例：

@javax.persistence.Column(name = "active_date")
private org.joda.time.DateTime activeDate;

最后，修复了persistence.xml文件：

<?xml version="1.0" encoding="UTF-8"?>
<persistence xmlns="http://java.sun.com/xml/ns/persistence" version="2.0">
    <persistence-unit name="testPU" transaction-type="RESOURCE_LOCAL">
        <provider>org.hibernate.jpa.HibernatePersistenceProvider</provider>
        <exclude-unlisted-classes>true</exclude-unlisted-classes>

这里有很多课程，所以我将它们剪掉以保持可读性

        <properties>
            <property name="javax.persistence.jdbc.driver" value="org.h2.Driver" />
            <property name="javax.persistence.jdbc.url" value="jdbc:h2:mem:test;MODE=PostgreSQL;INIT=create schema if not exists test;DB_CLOSE_DELAY=-1" />
            <property name="javax.persistence.jdbc.user" value="sa" />
            <property name="javax.persistence.jdbc.password" value="" />
            <property name="hbm2ddl.auto" value="create" />
            <property name="hibernate.dialect" value="org.hibernate.dialect.PostgreSQL9Dialect"/>
            <property name="hibernate.show_sql" value="false"/>
            <property name="jadira.usertype.autoRegisterUserTypes" value="true"/>
            <property name="jadira.usertype.databaseZone" value="jvm"/>
            <property name="jadira.usertype.javaZone" value="jvm"/>
        </properties>
    </persistence-unit>
</persistence>

Hibernate ClassCastException org.hibernate.type.SerializableType无法强制转换为org.hibernate.type.VersionType

1 个答案: