Question

我正在尝试提取在分类广告网站（http://trademe.co.nz/Trade-Me-Motors/Cars/Toyota/Hiace/auction-300294634.htm）上提问的用户。由于某些原因，我使用的模式并不总是如此，所以如果你能帮助我完美的正则表达式，我将不胜感激这是我目前的代码

/get memberid of the question asker
   $pattern = "//m";
   preg_match_all($pattern, $htmlContent, $member_match);

   $no_a = count($member_match[1];);            

   $inc = 0;

  echo "number of askers is $no_a";

  //make loop to get all the members
     while($inc ";
//get member user match based on the member_id
      $pattern2 = "/(.*)/";
     preg_match_all($pattern2, $htmlContent, $member_user_match);
      $bid_user_q = $member_user_match[1][0];
//store the askers
    mysql_query("INSERT INTO askers (id, item_number, bid_user_q, bid_member_id_q, sub_cat)
                             VALUES('', '$item_number', '$bid_user_q', '$bid_member_id_q', '$sub_cat')");
echo "INSERT INTO askers (id, item_number, bid_user_q, bid_member_id_q)
                             VALUES('', '$item_number', '$bid_user_q', '$bid_member_id_q', '$sub_cat')
";
mysql_error();
     $inc++; 

     }

由于模式中的html标记，代码似乎无法正常显示，因此您可以在此处查看http://pastebin.com/iPxizy5X

Answer 1

我怀疑它是“完美的”，但这个对我有用：

/<small>\s*<a href=\"\/Members\/Listings\.aspx\?member=(\d+)\">\s*<b>(.*?)<\/b>/

如果您使用：

$pattern = "/<small>\s*<a href=\"\/Members\/Listings\.aspx\?member=(\d+)\">\s*<b>(.*?)<\/b>/";
preg_match_all($pattern, $htmlContent, $member_match, PREG_SET_ORDER);

$ member_match [0] [1] =会员ID $ member_match [0] [2] =会员昵称 $ member_match [1] [1] =会员ID $ member_match [1] [2] =会员尼克

php preg_match_all，正则表达式，提取特定值

1 个答案: