我想知道是否/如何在XSLT中完成以下操作。如果没有,你会用什么? (我使用过OmniMark,但我想知道这是否可以在XSLT中使用。)
以下是输入XML的示例:
<?xml version="1.0" encoding="UTF-8"?>
<fragment>
<firstElem>
<secondElem>D12</secondElem>
</firstElem>
<firstElem>
<secondElem>A3J7-10</secondElem>
</firstElem>
<firstElem>
<secondElem>C2-4</secondElem>
</firstElem>
<firstElem>
<secondElem>QW9R7NP20-25</secondElem>
</firstElem>
</fragment>
我需要做的是获取secondElem
元素的文本内容,并根据需要创建尽可能多的新firstElem
元素。 ' - '是一个“通过”,所以'A3J7-10'实际上是'A3J7'到'A3J10'(A3J7,A3J8,A3J9,A3J10)。 (有时候“穿透”会相当大,比如A1B2C1-150(A1B2C1到A1B2C150)。)
如果没有破折号,则无需任何操作。
以下是输出XML的示例:
<?xml version="1.0" encoding="UTF-8"?>
<fragment>
<firstElem>
<secondElem>D12</secondElem>
</firstElem>
<firstElem>
<secondElem>A3J7</secondElem>
</firstElem>
<firstElem>
<secondElem>A3J8</secondElem>
</firstElem>
<firstElem>
<secondElem>A3J9</secondElem>
</firstElem>
<firstElem>
<secondElem>A3J10</secondElem>
</firstElem>
<firstElem>
<secondElem>C2</secondElem>
</firstElem>
<firstElem>
<secondElem>C3</secondElem>
</firstElem>
<firstElem>
<secondElem>C4</secondElem>
</firstElem>
<firstElem>
<secondElem>QW9R7NP20</secondElem>
</firstElem>
<firstElem>
<secondElem>QW9R7NP21</secondElem>
</firstElem>
<firstElem>
<secondElem>QW9R7NP22</secondElem>
</firstElem>
<firstElem>
<secondElem>QW9R7NP23</secondElem>
</firstElem>
<firstElem>
<secondElem>QW9R7NP24</secondElem>
</firstElem>
<firstElem>
<secondElem>QW9R7NP25</secondElem>
</firstElem>
</fragment>
有没有办法在XSLT中执行此操作?
谢谢!
答案 0 :(得分:2)
此样式表:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" exclude-result-prefixes="xsl">
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="firstElem[contains(.,'-')]" name="firstElem">
<xsl:param name="from">
<xsl:call-template name="getfrom"/>
</xsl:param>
<xsl:param name="base" select="normalize-space(substring-before(.,concat($from,'-')))"/>
<xsl:param name="to" select="substring-after(.,'-')"/>
<xsl:if test="$to >= $from">
<firstElem>
<secondElem>
<xsl:value-of select="concat($base,$from)"/>
</secondElem>
</firstElem>
<xsl:call-template name="firstElem">
<xsl:with-param name="from" select="$from + 1"/>
<xsl:with-param name="base" select="$base"/>
<xsl:with-param name="to" select="$to"/>
</xsl:call-template>
</xsl:if>
</xsl:template>
<xsl:template name="getfrom">
<xsl:param name="string" select="substring-before(.,'-')"/>
<xsl:variable name="last" select="substring($string,string-length($string))"/>
<xsl:if test="contains('0123456789',$last)">
<xsl:call-template name="getfrom">
<xsl:with-param name="string" select="substring($string,1,string-length($string)-1)"/>
</xsl:call-template>
<xsl:value-of select="$last"/>
</xsl:if>
</xsl:template>
</xsl:stylesheet>
输出:
<fragment>
<firstElem>
<secondElem>D12</secondElem>
</firstElem>
<firstElem>
<secondElem>A3J7</secondElem>
</firstElem>
<firstElem>
<secondElem>A3J8</secondElem>
</firstElem>
<firstElem>
<secondElem>A3J9</secondElem>
</firstElem>
<firstElem>
<secondElem>A3J10</secondElem>
</firstElem>
<firstElem>
<secondElem>C2</secondElem>
</firstElem>
<firstElem>
<secondElem>C3</secondElem>
</firstElem>
<firstElem>
<secondElem>C4</secondElem>
</firstElem>
<firstElem>
<secondElem>QW9R7NP20</secondElem>
</firstElem>
<firstElem>
<secondElem>QW9R7NP21</secondElem>
</firstElem>
<firstElem>
<secondElem>QW9R7NP22</secondElem>
</firstElem>
<firstElem>
<secondElem>QW9R7NP23</secondElem>
</firstElem>
<firstElem>
<secondElem>QW9R7NP24</secondElem>
</firstElem>
<firstElem>
<secondElem>QW9R7NP25</secondElem>
</firstElem>
</fragment>
答案 1 :(得分:1)
这是一个XSLT 2.0解决方案:
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
exclude-result-prefixes="xs">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:template match="node()|@*">
<xsl:copy>
<xsl:apply-templates select="node()|@*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="firstElem[contains(secondElem, '-')]">
<xsl:analyze-string select="secondElem"
regex="(^.*[^\d])([\d]*)-([\d]*)">
<xsl:matching-substring>
<xsl:variable name="vbaseName" select="regex-group(1)"/>
<xsl:variable name="vstart" select="regex-group(2)"/>
<xsl:variable name="vend" select="regex-group(3)"/>
<xsl:for-each select=
"xs:integer($vstart) to xs:integer($vend)">
<firstElem>
<secondElem>
<xsl:value-of select="concat($vbaseName, .)"/>
</secondElem>
</firstElem>
</xsl:for-each>
</xsl:matching-substring>
</xsl:analyze-string>
</xsl:template>
</xsl:stylesheet>
在提供的XML文档上应用上述转换时:
<fragment>
<firstElem>
<secondElem>D12</secondElem>
</firstElem>
<firstElem>
<secondElem>A3J7-10</secondElem>
</firstElem>
<firstElem>
<secondElem>C2-4</secondElem>
</firstElem>
<firstElem>
<secondElem>QW9R7NP20-25</secondElem>
</firstElem>
</fragment>
产生了想要的正确结果:
<fragment>
<firstElem>
<secondElem>D12</secondElem>
</firstElem>
<firstElem>
<secondElem>A3J7</secondElem>
</firstElem>
<firstElem>
<secondElem>A3J8</secondElem>
</firstElem>
<firstElem>
<secondElem>A3J9</secondElem>
</firstElem>
<firstElem>
<secondElem>A3J10</secondElem>
</firstElem>
<firstElem>
<secondElem>C2</secondElem>
</firstElem>
<firstElem>
<secondElem>C3</secondElem>
</firstElem>
<firstElem>
<secondElem>C4</secondElem>
</firstElem>
<firstElem>
<secondElem>QW9R7NP20</secondElem>
</firstElem>
<firstElem>
<secondElem>QW9R7NP21</secondElem>
</firstElem>
<firstElem>
<secondElem>QW9R7NP22</secondElem>
</firstElem>
<firstElem>
<secondElem>QW9R7NP23</secondElem>
</firstElem>
<firstElem>
<secondElem>QW9R7NP24</secondElem>
</firstElem>
<firstElem>
<secondElem>QW9R7NP25</secondElem>
</firstElem>
</fragment>
请注意:
使用正则表达式。
子表达式捕获和regex-group()
函数。
使用<xsl:analyze-string>
和<xsl:matching-substring>
。
使用to
运算符创建要在<xsl:for-each>
中使用的序列
在一系列非节点(整数)上使用<xsl:for-each>
。