Question

我正试图从我使用jpa存储库的列表中获取分页。 List实际上是另一个对象的属性。它是，有点像，好消息，留言板...长话短说，Tiket类有一个Poruka列表，我想要检索和分页。这是它的样子：

@Entity
@Table(name = "tiket")
public class Tiket implements Serializable {

    /**
     * 
     */
    private static final long serialVersionUID = 1L;

    @Id
    @GeneratedValue
    @Column(name="id")
    private Long id;

    @Column(name="naslov")
    @NotEmpty(message= "Morate unijeti naslov tiketa")
    private String naslov;

    @Column(name = "tiket_datum")
    @DateTimeFormat(pattern = "yyyy-MM-dd HH:mm:ss")
    @NotNull
    private Date tiketDatum;

    @Column(name = "rijesen_datum")
    @DateTimeFormat(pattern = "yyyy-MM-dd HH:mm:ss")
    private Date rijesenDatum;

    @ManyToOne(cascade = {CascadeType.REFRESH}, fetch=FetchType.EAGER )
    @JoinColumn(nullable=false)
    @NotNull
    private Korisnik korisnik;

    @OneToMany(cascade = {CascadeType.ALL}, fetch=FetchType.EAGER )
    @GenericGenerator(name="uuid-gen", strategy = "increment") 
    @CollectionId(columns = @Column(name = "collection_id"), generator = "uuid-gen", type = @Type(type = "long"))
    private List<Poruka> poruke = new ArrayList<Poruka>();

行。 Poruka清单是我需要的。所以我尝试在PorukaRepository中创建自定义查询，通过这样做得到Poruka的分页列表：

public interface PorukaRepository extends JpaRepository<Poruka, Long> {

    @Query("select t.poruke from Tiket t where t.id=?1")
    Page<Poruka> findAllPoruke(Long tid, Pageable pageable);
}

并收到以下错误：

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ') as col_0_0_ from tiket2 tiket2x0_, tiket2_poruka poruke1_, poruka poruka2_ whe' at line 1

然后尝试更改查询，因为数据库有tiket_poruka表，对此：

@Query(value="SELECT * FROM poruka p where p.id IN (SELECT tp.poruke_id FROM tiket_poruka tp WHERE tp.tiket_id=?0)", nativeQuery = true)

每次在编译期间收到以下错误：

No property find found for type ba.fit.vms.pojo.Poruka

然后试图把它放在TiketRepository中......没有运气。然后我添加了order by并排序到我的查询，仍然没有运气。

这次错误是它无法从Tiket转换为Poruka

当然，我可以检索列表并在我的控制器中对其进行分页，但我想学习并查看是否可行，因为它似乎合乎逻辑。我需要创建自定义存储库吗？或者只是我的查询错了？

这是Poruka.class：

@Entity
@Table(name = "poruka")
public class Poruka  implements Serializable{ //, Comparable<Poruka>

    /**
     * 
     */
    private static final long serialVersionUID = 1L;

    @Id
    @GeneratedValue
    @Column(name="id")
    private Long id;

    @Column(name="sadrzaj", length = 255)
    @NotEmpty(message= "Sadrzaj ne moze biti prazan")
    private String sadrzaj;

    @Column(name = "datum")
    @DateTimeFormat(pattern = "yyyy-MM-dd HH:mm:ss")
    @NotNull
    private Date datum;

    @OneToOne(fetch=FetchType.EAGER)
    @JoinColumn(name="korisnik_id", nullable=true)
    private Korisnik korisnik;

    @OneToOne(fetch=FetchType.EAGER)
    @JoinColumn(name="prethodna_id", nullable=true)
    private Poruka prethodni;

当然，课程没有getter和setter ......

spring jpa自定义查询返回页面<e>

0 个答案: