Question

因此有一个完全独立的问题（我认为）将数组保存到mongo文档中。所以我拿出那个部分，创建了一个具有相同问题的数据结构来尝试解决它。但是现在我的测试代码似乎在save函数返回之前完成，只是不确定如何解决这两个问题，或者它们是否可能已连接。

猫鼬模式：

var mongoose = require('mongoose');
ObjectId = mongoose.Schema.Types.ObjectId;

var offerSchema = mongoose.Schema({
    closeDate: Date,
    settleDate: Date,
    schemaVersion: Number,
    _offered: [{ type: ObjectId, ref: 'User'}], //Ids of thos offered
    _offerDate: { type: Date },// The date they where offered
    _accepted: [{ type: ObjectId, ref: 'User'}],//Ids of those accepted
    _acceptedDate: [{ type: Date }], //Dates when accepted
});



// create the model for users and expose it to our app
module.exports = mongoose.model('offer', offerSchema);

所以我编写了下面的代码来重新创建问题，下面的代码应该可以工作但不能在_offered中存储一个值。

var offer = require('../models/offerSchema.js')
var indata = {"offer":{"closeDate":"2015-08-31T13:26:36.512Z","settleDate":"2015-08-31T13:26:36.512Z","type":1,"_offered":[{"id":"55dc7994ed0fcf4a58d4a689"},{"id":"55dcd30915e3be545a51bebd"}],"_offerDate":"2015-08-31T13:26:36.512Z"}}

var thisOffer = indata.offer
for ( var i in thisOffer ){
    console.log("Got "+ i +" is " + thisOffer[i])

}
var myOffer = new offer(thisOffer);
myOffer._offered = undefined
var promise =
myOffer.save(function(err){
    if(err){
        console.log('Got an error: ' + err)
    }
    console.log('Got an id: ' + myOffer._id)
    return 0;
}).then(function() {
    console.log("I get here and quit?");
})

但是，代码似乎在保存完成之前完成，我实际上不确定如何避免这种情况。

Answer 1

好的，发现了这个问题。 mongoose save没有被宣传（或者至少那是我调查的问题），更改了第一部分使用bluebird for promises，然后将save更改为使用saveAsync，如下所示架构（以及连接和蓝鸟）

var mongoose = require('mongoose');
var Promise = require('bluebird');
Promise.promisifyAll(mongoose);
mongoose.connect('mongodb://webbetcha:M0t0rWrl3d@localhost/betchadb');
ObjectId = mongoose.Schema.Types.ObjectId;

var offerSchema = mongoose.Schema({
    closeDate: Date,
    settleDate: Date,
    schemaVersion: Number,
    _offered: [{ type: ObjectId, ref: 'User'}], //Ids of thos offered
    _offerDate: { type: Date },// The date they where offered
    _accepted: [{ type: ObjectId, ref: 'User'}],//Ids of those accepted
    _acceptedDate: [{ type: Date }], //Dates when accepted
});



// create the model for users and expose it to our app
module.exports = mongoose.model('offer', offerSchema);

代码

var offer = require('../models/offerSchema.js');

var indata = {"offer":{"closeDate":"2015-08-31T13:26:36.512Z","settleDate":"2015-08-31T13:26:36.512Z","type":1,"_offered":[{"id":"55dc7994ed0fcf4a58d4a689"},{"id":"55dcd30915e3be545a51bebd"}],"_offerDate":"2015-08-31T13:26:36.512Z"}}

var thisOffer = indata.offer
for ( var i in thisOffer ){
    console.log("Got "+ i +" is " + thisOffer[i])

}
var myOffer = new offer(thisOffer);
myOffer._offered = undefined
myOffer.saveAsync()
.then(function(doc){
        console.log('Got an id: ' + myOffer._id)
    })
.catch(function(err){
    if(err){
        console.log('Got an error: ' + err)
    }
});

Answer 2

您正在将逻辑与回调和承诺混合在一起。所以你不需要回调，只需对返回的承诺采取行动：

myOffer._offered = undefined
myOffer.save()
  .then(function() {
    console.log("I get here and quit?");
  })
  .then(null,function(err) {
      console.log(err);
  });

我注意到您使用Bluebird承诺再次尝试，但没有必要像您在此处所示实现任何错误将被适当地路由。

Threre指出，mongooose 5.x预计将采用更标准化的承诺方式和/或在配置时直接使用Bluebird承诺

猫鼬似乎悄然失败

2 个答案: