Question

我已经在Parse.com的User类中上传了另一个数组列，我希望将该数组返回并在表视图中显示它。该数组是用户键入的阻止用户列表。

NSString *usernameBlock = [self.blockUser.text];

PFUser *blockedUser = [PFUser currentUser];
[blockedUser addObject:usernameBlock forKey:@"blockedUsers"];
self.blockedRelation = [blockedUser relationForKey:@"blocked"];
[blockedUser saveInBackground];

这会添加另一个用户名数组列。

现在在我的blockedUserVC中，我想查询该列并让数组显示在tableView中。

我试过以下但我一直在崩溃： -

//tried this
PFQuery *query = [PFQuery queryWithClassName:@"_User"];
[query whereKey:@"blockedUsers" equalTo:[PFUser currentUser]];
[query valueForKey:@"blockedUsers"];
[query whereKey:@"blockedUsers" containedIn:_blockedUser]; //blocked user is an array
[query orderByAscending:@"username"];
[query findObjectsInBackgroundWithBlock:^(NSArray *objects, NSError *error){
    if (error) {
        //  NSLog(@"error %@ %@", error, [error userInfo]);
    } else {
        self.blockedUser = objects; //blockedUser is an array
        [self.tableView reloadData];
    }
}];

我应该如何查询，以便获得该数组？

    crashlog:
    Terminating app due to uncaught exception 'NSUnknownKeyException', reason: 
'[<PFQuery 0x7fc13150fbe0> valueForUndefinedKey:]: this class is not key value coding-compliant for the key blockedUsers.'

Answer 1

[query valueForKey:@"blockedUsers"];

此行导致崩溃，请改用use include。 https://parse.com/docs/ios/guide

另外，我认为：

[query whereKey:@"blockedUsers" containedIn:_blockedUser]; //blocked user is an array

应该是：

[query whereKey:@"blockedUsers" containsAllObjectsInArray:@[_blockedUser]]; //blocked user is an array

这不会导致崩溃，但它会屈服于（据我所知）错误的结果。

检索数组并在tableView iOS Parse.com中显示

1 个答案: