Question

我有一个带有Hibernate依赖项的Spring MVC项目：

<dependency>
<groupId>org.hibernate</groupId>
<artifactId>hibernate-core</artifactId>
<version>5.0.0.Final</version>
</dependency>

<!-- for JPA, use hibernate-entitymanager instead of hibernate-core -->
<dependency>
<groupId>org.hibernate</groupId>
<artifactId>hibernate-entitymanager</artifactId>
<version>5.0.0.Final</version>
</dependency>

<!-- optional -->

<dependency>
<groupId>org.hibernate</groupId>
<artifactId>hibernate-osgi</artifactId>
<version>5.0.0.Final</version>
</dependency>
<dependency>
<groupId>org.hibernate</groupId>
<artifactId>hibernate-envers</artifactId>
<version>5.0.0.Final</version>
</dependency>
<dependency>
<groupId>org.hibernate</groupId>
<artifactId>hibernate-c3p0</artifactId>
<version>5.0.0.Final</version>
</dependency>
<dependency>
<groupId>org.hibernate</groupId>
<artifactId>hibernate-proxool</artifactId>
<version>5.0.0.Final</version>
</dependency>
<dependency>
<groupId>org.hibernate</groupId>
<artifactId>hibernate-infinispan</artifactId>
<version>5.0.0.Final</version>
</dependency>
<dependency>
<groupId>org.hibernate</groupId>
<artifactId>hibernate-ehcache</artifactId>
<version>5.0.0.Final</version>
</dependency>

这是我的简单控制器：

@EnableTransactionManagement
@Controller
public class HomeController {

@PersistenceContext
private EntityManager em;

@Transactional
@RequestMapping("/home")
public String goHome(){
    System.out.println(em);
    return "home";
    }
}

的applicationContext.xml：

 <?xml version="1.0" encoding="UTF-8"?>
 <beans xmlns="http://www.springframework.org/schema/beans"
  xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
  xsi:schemaLocation="http://www.springframework.org/schema/beans  
  http://www.springframework.org/schema/beans/spring-beans.xsd">

 <beans>

 <bean id="myEmf"                                                                  
 class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
 <property name="dataSource" ref="someDataSource"/>
 <property name="loadTimeWeaver">
 <bean class="org.springframework.instrument.classloading.
              InstrumentationLoadTimeWeaver"/>
 </property>
 </bean>

我不确定我应该放在这里：

 <property name="dataSource" ref="someDataSource"/>

hibernate的dataSource参考是什么？这条配置来自spring dokumentation

Answer 1

试试这个应用程序上下文xml：

Array
(
    [0] => Germany
    [1] => "Sightseeing, Travelling, Hotels"
)

Answer 2

查看下面的spring配置（dataSource，组件扫描目录和hibernate属性应根据您的需要进行调整）：

<beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xmlns:jpa="http://www.springframework.org/schema/data/jpa"
       xmlns:tx="http://www.springframework.org/schema/tx"
       xmlns:context="http://www.springframework.org/schema/context"
       xmlns:aop="http://www.springframework.org/schema/aop"

   xsi:schemaLocation="http://www.springframework.org/schema/beans
        http://www.springframework.org/schema/beans/spring-beans.xsd
        http://www.springframework.org/schema/context
        http://www.springframework.org/schema/context/spring-context.xsd
        http://www.springframework.org/schema/data/jpa
        http://www.springframework.org/schema/data/jpa/spring-jpa.xsd
        http://www.springframework.org/schema/tx
        http://www.springframework.org/schema/tx/spring-tx.xsd
        http://www.springframework.org/schema/aop
        http://www.springframework.org/schema/aop/spring-aop.xsd">

// will enable jpa repositories if you use one
    <jpa:repositories base-package="com.xyz.database.repository"/>
// allow usage of transactional annotation
    <tx:annotation-driven transaction-manager="transactionManager"/>
//scans for spring components
    <context:component-scan base-package="com.xyz"/>
// dataSource creates connection to database
<bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource">
    <property name="driverClassName" value="${jdbc.driverClassName}"/>
    <property name="url" value="${jdbc.url}"/>
    <property name="password" value="${jdbc.password}"/>
    <property name="username" value="${jdbc.username}"/>
</bean>

// create entity manager 
    <bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
        <property name="dataSource" ref="dataSource"/>
        <property name="jpaVendorAdapter" ref="jpaVendorAdapter"/>
        <property name="packagesToScan" value="com.xyz"/>
        <property name="jpaProperties">
            <props>
                <prop key="hibernate.dialect">org.hibernate.dialect.Oracle10gDialect</prop>
                <prop key="hibernate.jdbc.fetch_size">10000</prop>
                <prop key="hibernate.connection.autocommit">true</prop>
                <prop key="hibernate.jdbc.batch_size">100</prop>
                <prop key="hibernate.show_sql">false</prop>
                <prop key="hibernate.format_sql">false</prop>
            </props>
        </property>
    </bean>

    <bean id="jpaVendorAdapter" class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter"/>

// create transaction manager 
    <bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
        <property name="entityManagerFactory" ref="entityManagerFactory"/>
        <property name="dataSource" ref="dataSource"/>
        </bean>
</beans>

之后你可以使用：

@PersistenceContext
private EntityManager em;

Spring MVC控制器中的EntityManager为null

2 个答案: