Question

有两个表，用户和拍卖，我试图获得赢得最多胜利的用户的id，firstname和lastname在特定时间，胜利由具有值1的a.closed验证。

 SELECT a.winner_id AS 'Winners.id', u.first_name AS 'Winners first name', u.last_name AS 'Winners last name',
                            COUNT( * ) as count
                            FROM    auctions a
                            RIGHT JOIN users u ON a.winner_id = u.id
                            GROUP BY a.winner_id
                            ORDER BY a.winner_id
                            WHERE a.closed = '1' DESC AND
                            BETWEEN '".$dateFrom." 00:00:00' AND '".$dateTo." 23:59:59'
                            LIMIT    1

不幸的是我收到了这个错误：

  #1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'WHERE a.closed = '1' DESC AND BETWEEN '".$dateFrom." 00:00:00' AND '".$' at line 7

Answer 1

where子句附近的语法不正确。 DESC和ASC基本上与ORDER BY子句一起使用。

接下来，GROUP BY子句和ORDER BY子句位于where子句之后。您需要浏览MYSQL manual以详细查找语法。

所以你试试

SELECT a.winner_id AS 'Winners.id', u.first_name AS 'Winners first name', u.last_name AS 'Winners last name',
 COUNT( * ) as count
 FROM    auctions a
  RIGHT JOIN users u ON a.winner_id = u.id
   WHERE a.closed = '1' AND
   datecolumn BETWEEN  '00:00:00' AND  '23:59:59' --Change it as per your datecolumn name
   GROUP BY a.winner_id
   ORDER BY a.winner_id DESC 
   LIMIT    1

Answer 2

你的语法错了。必须是select .. from ... join .. where ..group by .. order by ...

SELECT a.winner_id AS 'Winners.id', u.first_name AS 'Winners first name', u.last_name AS 'Winners last name',
COUNT(*) as count
FROM  auctions a
RIGHT JOIN users u ON a.winner_id = u.id
WHERE a.closed = '1' AND
BETWEEN '".$dateFrom." 00:00:00' AND '".$dateTo." 23:59:59'
GROUP BY a.winner_id
ORDER BY a.winner_id DESC 
LIMIT 1

Answer 3

您可以在查询结束时进行订购，对于desc，您需要首先使用某个列的订单。

您可以尝试以下 -

SELECT a.winner_id AS 'Winners.id', u.first_name AS 'Winners first name', u.last_name AS 'Winners last name',
                            COUNT( * ) as count
                            FROM    auctions a
                            RIGHT JOIN users u ON a.winner_id = u.id
                            WHERE a.closed = '1' 
                            and BETWEEN '".$dateFrom." 00:00:00' AND '".$dateTo." 23:59:59'
                            group by a.winner_id 
                            order by a.winner_id desc LIMIT    1

Answer 4

WHERE ...必须位于select语句中的GROUP BY ...之前。

尝试更改此内容。

请参阅：https://dev.mysql.com/doc/refman/5.6/en/select.html

如果您需要选择并排序然后从中进行选择，则应使用子查询。

见这里：https://dev.mysql.com/doc/refman/5.6/en/from-clause-subqueries.html

Answer 5

GOT IT谢谢大家。选择a.winner_id AS＆＃39;用户ID＆＃39;，u.first_name AS＆＃39;名字＆＃39;，u.last_name AS＆＃39;姓氏＆＃39;，COUNT（）AS ＆＃39;赢得的拍卖数量＆＃39; 来自拍卖a RIGHT JOIN用户u on a.winner_id = u.id a.closed =＆＃39; 1＆＃39;和a.end_time BETWEEN＆＃39;＆＃34;。$ dateFrom。＆＃34; 00：00：00＆＃39; AND＆＃39;＆＃34;。$ dateTo。＆＃34; 23：59：59＆＃39; GROUP BY a.winner_id 按计数排序（）DESC 限制1

SQL语句错误：我想选择获胜最多的用户

5 个答案: