Question

s1 ='a,b,c,"x,y,z" '
m1 = s1.split(',')

"x,y,z"不应该用逗号分隔

预期结果应为['a'，'b'，'c'，“x，y，z”]，总大小为4

我怎么能在Ruby中做到这一点

Answer 1

使用csv模块：

irb(main):001:0> require 'csv'
=> true
irb(main):002:0> CSV.parse_line('a,b,c,"x,y,z"')
=> ["a", "b", "c", "x,y,z"]

Answer 2

试试这个：

s1 ='a,b,c,"x,y,z" '

quotes = s1.match(/".+"/)

s1.split(/,(?![#{quotes}])|,(?=")/)

Answer 3

可能吗？可能吗？我是否终于有机会使用Ruby的奇异边界flip-flop operator？

让我们试试：

str ='a,b,c,"x,y,z",d,e,"1,2,3",f '

u = ''  
str.split(?,).each_with_object([]) do |s,a|
  t = s.strip
  if (t[0]==?") .. (t[-1]==?")
    u = '' if t[0]==?"
    u << t
    if t[-1]==?"
      a << u
    else
      u << ?,
    end
  else
    a << t
  end
end
  #=> ["a", "b", "c", "\"x,y,z\"", "d", "e", "\"1,2,3\"", "f"]

Answer 4

你可以像这样做一个单词def，用逗号分隔字符串，除非逗号在简单的OR双引号内

def to_structure(lst, stru):
  lst = iter(lst)
  for elem in stru:
    if isinstance(elem, list):
      yield list(to_structure(lst, elem))
    else:
      yield next(lst, None) # replace missing elements with None
      # alternately, raise ValueError (see also pep 479)
      # try:
      #   yield next(lst)
      # except StopIteration:
      #   raise ValueError("Not enough elements")

list(to_structure(range(4), [[0,0],[0],[[0]]])) # -> [[0, 1], [2], [[3]]]
list(to_structure(range(3), [[0,0],[0],[[0]]])) # -> [[0, 1], [2], [[None]]]

我怎么能用双引号分割逗号除外

4 个答案: