Question

我使用此查询从用户已达到的最高章节中拉出最高级别的遭遇：

SELECT COUNT(hc.s) as users, highest_chapter, highest_encounter
FROM
(
  SELECT s, MAX(l) as highest_chapter
  FROM appl9_evt
  WHERE month = "201508" AND st1 = "player" AND st2 = "level_progression" AND n = "level_start"
  GROUP BY s
  ORDER BY highest_chapter
) hc
INNER JOIN
(
  SELECT s, l, MAX(get_json_object(json_data, '$.CurrentEncounter')) as highest_encounter 
  FROM appl9_evt
  WHERE month = "201508" AND st1 = "player" AND st2 = "level_progression" AND n = "level_start"
  GROUP BY s, l
  ORDER BY highest_encounter
) he ON hc.s = he.s AND hc.highest_chapter = he.l 
GROUP BY highest_chapter, highest_encounter

然后我把它保存为一个表，并尝试只获得版本2.2.1（或任何版本，我认为它被称为自我加入）：

SELECT COUNT(DISTINCT highest.s) as users, highest_chapter, highest_encounter FROM
(
  SELECT users as s, highest_chapter, highest_encounter 
  FROM augusers221
) highest
INNER JOIN
(
  SELECT s 
  FROM appl9_cpu
  WHERE v_maj = '2.2.1'
) ver ON highest.s = ver.s
GROUP BY highest_chapter, highest_encounter
ORDER BY highest_chapter, highest_encounter

但是第二阶段出现了问题，因为我无法提取任何数据......请提前感谢您查看此文本墙。

Answer 1

我无法确定没有样本数据且列名不友好。但似乎s列包含用户名或ID。是对的吗？

如果是这样，那么您无法将其加入augusers221.users列，因为它是一个用户数。

您可以在第一个查询中加入appl9_cpu表，我认为您需要，因为您在第二次查询时已经丢失了用户名/ ID。< / p>

SELECT COUNT(hc.s) as users, highest_chapter, highest_encounter
FROM
(
  SELECT s, MAX(l) as highest_chapter
  FROM appl9_evt
  WHERE month = "201508" AND st1 = "player" AND st2 = "level_progression" AND n = "level_start"
  GROUP BY s
  ORDER BY highest_chapter
) hc
INNER JOIN
(
  SELECT s, l, MAX(get_json_object(json_data, '$.CurrentEncounter')) as highest_encounter 
  FROM appl9_evt
  WHERE month = "201508" AND st1 = "player" AND st2 = "level_progression" AND n = "level_start"
  GROUP BY s, l
  ORDER BY highest_encounter
) he ON hc.s = he.s AND hc.highest_chapter = he.l
INNER JOIN appl9_cpu cpu ON cpu.s = hc.s
WHERE cpu.v_maj = '2.2.1' 
GROUP BY highest_chapter, highest_encounter

如果这没有帮助，那么也许您可以发布一些样本数据。

Answer 2

从我所看到的这个小提琴：http://sqlfiddle.com/#!9/1026d/3 问题是由于SELECT COUNT(hc.s) as users,稍后将其加入s中的ON highest.s = ver.s时导致的。所以，你加入计数到实际价值。

如果您将列名更改为更明确，则问题可能更清楚。

为什么我没有使用这些HQL查询获取任何数据？

2 个答案: