Question

我正在寻找一种尽可能高效完成此任务的方法。以下是我希望它如何工作。用户输入

"My screen is broken"

该脚本找到两个关键字＆＃34; screen＆＃34;和＃34;破碎＆＃34;然后打印一个合适的字符串。作为一个菜鸟我以为我可以使用像这样的字典

{"screen", "broken", "smashed":"use a repair kit"}

然后我会搜索字典中的所有键。但经过进一步的研究，这似乎是不可能的。

那么最好的方法是什么呢？我想也许是sql，但我想知道是否有更好的方法只涉及python.Thanks

Answer 1

字典键需要是不可变的，你可以使用元组，例如

# {("screen", "broken"): "use a repair kit"}

# input is a keyword in Python, so use input_ instead
input_ = input_.split()
if 'screen' in input_ and 'broken' in input_:
    return "use a repair kit"

Answer 2

str_replace()

Answer 3

如果你只是在寻找“屏幕”和“破碎”，这样的事情就可以了。

sentence = "My screen is broken"
keys = ["screen", "broken"]

if all(i in sentence for i in keys):
    print "Use a repair kit"

Answer 4

根据zyxue的回答，您可以检查某些值，但不是全部。这将适用于您的上述代码，但如果您想将其他名称分组，则可以将多个元组嵌套在一起。

sentence = "My screen is smashed"

solution_dict = {}
solution_dict[("screen", ("broken", "smashed"))] = "use a repair kit"

#If value is a tuple, run function on every value and return if there are any matches
#If not, check the word is part of the sentence
def check_match(sentence_words, keyword):
    if isinstance(keyword, tuple):
        return any([check_match(sentence_words, i) for i in keyword])
    return keyword in sentence_words

#Make sure each value in the main tuple has a match
sentence_words = [i.lower() for i in sentence.split()]
for k,v in solution_dict.iteritems():
    if all(check_match(sentence_words, i) for i in k):
        print v

所以你会得到这样的结果：

>>> sentence = "My screen is smashed"
use a repair kit
>>> sentence = "My screen is smashed and broken"
use a repair kit
>>> sentence = "My screen is broken"
use a repair kit
>>> sentence = "My phone is broken"
(nothing)

要使用手机，还有iphone和android，你可以这样设置，让iphone和android在另一个元组没有区别，但只是将它组合得更好。
solution_dict[(("screen", "phone", ("android", "iphone")), ("broken", "smashed"))] = "use a repair kit" < / p>

在字符串中搜索多个关键字

4 个答案: