变更机器的代码工作100％，适用于CodeH的Python

Question

我在初学者编程课程。我们必须做一个改变制造者计划的练习。输入必须在0-99之间，并且当输入在四者之间分配时，必须以四分之一，硬币，镍币和便士表示。我编写了一个涉及循环和whiles的代码，但他想要更简单的代码和更小的代码。他给了我这个帮助我的方法：

<script type="text/javascript">  
$("document").ready(function() {
setTimeout(function() {
    $(".project").trigger('click');
    alert(1);
},10);
});
</script>

他告诉我们，这基本上就是我们所需要的，只需要添加硬币，镍币和硬币。我用硬币，镍币和硬币尝试多种方式，但我无法正确输出。每当我输入'99'时，我得到3分为四分之一，2分为硬币，1分为镍，0分为便士。如果有人能够帮助我，那将是美好的！

Answer 1

我现在确定你想要实现的目标。使用模数运算符，您可以轻松找出多少个季度，硬币，镍币和便士。

我们只说你输入99。

c=int(input('Please enter an amount between 0-99:'))
print(c//25, "quarters")
c = c%25
print(c//10, "dimes")
c = c%10
print(c//5, "nickles")
c = c%5
print(c//1, "pennies")

这将打印出来：

3 quarters
2 dimes
0 nickles
4 pennies

Answer 2

实际的诀窍是知道因为每枚硬币的价值至少是下一个较小面额的两倍you can use a greedy algorithm。其余的只是实施细节。

这是一个稍微干的（但可能，呃，更令人困惑）实现。我真正做的就是使用列表来存储我的结果，并利用tuple unpacking和divmod。此外，这在将来更容易扩展：我需要做的就是支持1美元账单，将coins更改为[100, 25, 10, 5, 1]。等等。

coins = [25,10,5,1] #values of possible coins, in descending order
results = [0]*len(coins) #doing this and not appends to make tuple unpacking work
initial_change = int(input('Change to make: ')) #use raw_input for python2
remaining_change = initial_change
for index, coin in enumerate(coins):
    results[index], remaining_change = divmod(remaining_change, coin)
print("In order to make change for %d cents:" % initial_change)
for amount, coin in zip(results, coins):
    print("    %d %d cent piece(s)" % (amount, coin))

给你：

Change to make: 99
In order to make change for 99 cents:
    3 25 cent piece(s)
    2 10 cent piece(s)
    0 5 cent piece(s)
    4 1 cent piece(s)

Answer 3

n = int(input("Enter a number between 0-99"))
q = n // 25
n %= 25
d = n // 10
n %= 10
ni =  n // 5
n %= 5
c = n % 5
print(str(q) +" " + str(d) +" " + str(ni) + " " + str(c))

我希望这有帮助吗？像这样的东西，但不要只是复制它。每当你除以25 10 5时，你必须丢失那部分，因为它已经被计算在内。最后打印你想要的东西:)。

Answer 4

""" 
  Change Machine - Made by A.S Gallery

  This program shows the use of modulus and integral division to find the quarters, nickels, dimes, pennies of the user change !!
  Have Fun Exploring !!!

"""

#def variables
user_amount = float(input("Enter the amount paid : "))
user_price = float(input("Enter the price : "))


# What is the change ?? (change calculation)
user_owe = user_amount - user_price

u = float(user_owe)

print "Change owed : " + str(u)


"""
    Calculation Program (the real change machine !!)

"""


# Variables for Calculating Each Coin !!
calculate_quarters = u//.25

# Using the built-in round function in Python !!
round(calculate_quarters)

print "Quarters : " + str(calculate_quarters)

u = u%0.25

calculate_dime = u//.10

round(calculate_dime)

print "Dime : " + str(calculate_dime)

u = u%0.10

calculate_nickels = u//.05  

round(calculate_nickels)

print "Nickels : " + str(calculate_nickels)

u = u%0.5

calculate_pennies = u//.01

round(calculate_pennies)

print "Pennies : " + str(calculate_pennies

变更机器的代码工作100％，适用于CodeH的Python

Answer 5

这可能是解决此问题的更简单方法之一，但是，它也可以用while循环减少重复次数

cents = int(input("Input how much money (in cents) you have, and I will tell 
you how much that is is quarters, dimes, nickels, and pennies. "))

quarters = cents//25
quarters_2 = quarters*25
dime = (cents-quarters_2)//10
dime_2 = dime*10
nickels = (cents-dime_2-quarters_2)//5
nickels_2 = nickels*5
pennies = (cents-dime_2-quarters_2-nickels_2)

硬币改变制造商Python程序

5 个答案:

变更机器的代码工作100％，适用于CodeH的Python