Question

尝试在tabviewcontroller序列中加载从前一个viewcontroller传递的url。检查通常的嫌疑人。 UIWebview添加了视图插座。所有适当的代表都已连接。我不确定NSURL是否会被传递到下一个视图控制器，因为我得到一个黑屏（尽管响应对象不是nil）。它让我发疯，因为这是一个简单的问题而且这是我做过数百万次的事情，但它不起作用。任何帮助，将不胜感激。

下面你会找到代码。

SquirrelInformationTableViewController.m

@interface ASAInformationTabViewController (){
    NSMutableArray *squirrelArray;
}
@property (nonatomic, strong) ODRefreshControl *refreshControl;
@property (weak, nonatomic) IBOutlet UITableView *squirrelListTableView;

@end

@implementation ASAInformationTabViewController

- (void)viewDidLoad {
    [super viewDidLoad];


    [self setUpSquirrelList];
    //Add drag to refresh function
    self.refreshControl = [[ODRefreshControl alloc]initInScrollView:self.squirrelListTableView];
    self.refreshControl.tintColor = [UIColor colorWithRed:46.0/255 green:172.0/255 blue:247.0/255 alpha:1];
    [self.refreshControl addTarget:self action:@selector(dragToRefreshAction:) forControlEvents:UIControlEventValueChanged];
}



-(void)setUpSquirrelList
{

    __weak UITableView* weaktable = self.squirrelListTableView;
    [[ASASquirrelManager instance] listSquirrels:^(NSString *response, NSMutableArray *result) {


        if ([response isEqualToString:CODE_SUCCESS]) {
            squirrelArray = result;
            dispatch_async(dispatch_get_main_queue(), ^{
                if (weaktable) {
                    [weaktable reloadData];
                }
            });
    }

    }];
}



-(UITableViewCell*)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
{
        ASASquirrelInformationTableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:@"squirrelIdentifier"];
        ASASquirrelModel *squirrelLocal = squirrelArray[indexPath.row];
        cell.squirrelTitleLabel.text = squirrelLocal.title;
        cell.squirrelDescLabel.text = squirrelLocal.desc;

        NSData *imageData = [[NSData alloc] initWithContentsOfURL:
                         [NSURL URLWithString:squirrelLocal.image]];
        cell.squirrelImage.image = [UIImage imageWithData:imageData];


        return cell;

}

-(void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath {
    ASASquirrelModel *squirrelWebLocal = squirrelArray[indexPath.row];

    NSString *squirrelURLString = squirrelWebLocal.url;
    //create an array with the string you want an access it
    NSLog(@"%@", urlStringArray);

    //Create a string from the URL pass it to the sdvc.string

    SquirrelDetailViewController *sdvc = [SquirrelDetailViewController new];
    sdvc.urlString = squirrelURLString;
    [self.navigationController pushViewController:sdvc animated:YES];

}

SquirrelDetailViewController.m

@interface SquirrelDetailViewController () <UIWebViewDelegate> 

@end

@implementation SquirrelDetailViewController

- (void)viewDidLoad {
    [super viewDidLoad];

    self.webView.frame = self.view.bounds;
    [self.view addSubview:self.webView];

}

-(void)viewWillAppear:(BOOL)animated
{

    self.urlstr = [NSURL URLWithString:self.urlString];
    NSURLRequest *requestObj = [NSURLRequest requestWithURL:self.urlstr];
    [self.webView loadRequest:requestObj];
}

Answer 1

我认为你需要使用故事板创建sdvc的实例，否则它将无法正确实例化。所以：

SquirrelDetailViewController *sdvc = 
  (SquirrelDetailViewController *)[[UIStoryboard storyboardWithName:@"XXX" bundle:nil] instantiateViewControllerWithIdentifier:@"YYY"];

其中XXX是您的故事板名称，YYY是SquirrelDetailViewController的故事板标识符。

Answer 2

我发现问题是我没有准备segue。（打前额*）

-(void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath {
    [self performSegueWithIdentifier:@"webviewpush" sender:self];
}

-(void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender
{
    if ([[segue identifier] isEqualToString:@"webviewpush"]) {

        // Get destination view
        SquirrelDetailViewController *vc = [segue destinationViewController];

        NSIndexPath *path = [self.squirrelListTableView indexPathForSelectedRow];

        ASASquirrelModel *squirrelWebLocal = squirrelArray[path.row];
        NSString *squirrelURLString = squirrelWebLocal.url;
        vc.urlString = squirrelURLString;

    }
}

如果你原谅我，我现在就要自己淹死了。

来自TabBarController的UITableview的UIWebView无法加载

2 个答案: