我创建了一个ajax提交按钮来提交表单 表格工作良好,我需要的所有功能都完美无缺 我也启用了Ajax验证和成功消息。 当我部分重定向表单时,会发生此问题。 ajax功能和验证无效。
我的控制器
public function actionCreate()
{
$model=new Comments;
// Uncomment the following line if AJAX validation is needed
$this->performAjaxValidation($model);
if(isset($_POST['Comments']))
{
$model->attributes=$_POST['Comments'];
// echo '<pre>';print_r($model->attributes);die();
$valid = $model->validate();
if($valid){
if($model->save()){
echo CJSON::encode(array('status'=>'success'
));
}
}else{
$error =CActiveForm::validate($model);
if($error != '[]')
echo $error;
Yii::app()->end();
}
}
}
查看/ _Form
<?php
$form = $this->beginWidget('CActiveForm',array('id'=>'comments-form',
'enableAjaxValidation'=>true,
'action'=>$this->createUrl('Comments/create'),
'enableClientValidation'=>true
));
?>
<div class="errorMessage" id="formResult"></div>
<div id="AjaxLoader" style="display:none" >
<img src="<?php echo Yii::app()->request->baseUrl;?>/theme/images/spinner.gif">
</div>
<div class="row-user-single-user-single" >
<?php echo $form->labelEx($model,'type'); ?>
<?php
echo $form->dropDownList($model,'type',
array(""=>"Select Type","0"=>"Offer","1"=>"Events"),
array('style' => 'width:220px;','class'=>'form-control','disabled'=>false,)); ?>
<?php echo $form->error($model,'type'); ?>
</div>
<div class="row-user-single-user-single" >
<?php echo $form->labelEx($model,'offereventid'); ?>
<?php echo $form->textField($model,'offereventid',array('style' => 'width:500px;','class'=>'form-control','disabled'=>false,)); ?>
<?php echo $form->error($model,'offereventid'); ?>
</div>
<div class="row-user-single-user-single">
<?php echo $form->labelEx($model,'name'); ?>
<?php echo $form->textField($model,'name',array('style' => 'width:500px;','class'=>'form-control','disabled'=>false,)); ?>
<?php echo $form->error($model,'name'); ?>
</div>
<div class="row-user-single">
<?php echo $form->labelEx($model,'email'); ?>
<?php echo $form->textField($model,'email',array('style' => 'width:500px;','class'=>'form-control','disabled'=>false,)); ?>
<?php echo $form->error($model,'email'); ?>
</div>
<div class="row-user-single">
<?php echo $form->labelEx($model,'comment'); ?>
<?php echo $form->textArea($model,'comment',array('style' => 'width:500px;','class'=>'form-control','disabled'=>false,)); ?>
<?php echo $form->error($model,'comment'); ?>
</div>
<div class="row-user-single">
<?php //echo $form->labelEx($model,'createdby'); ?>
<?php //echo $form->textField($model,'createdby'); ?>
<?php //echo $form->error($model,'createdby'); ?>
</div>
<div class="row-user-single">
<?php //echo $form->labelEx($model,'createdon'); ?>
<?php //echo $form->textField($model,'createdon'); ?>
<?php //echo $form->error($model,'createdon'); ?>
</div>
<div class="row-user-single">
<?php //echo $form->labelEx($model,'status'); ?>
<?php //echo $form->textField($model,'status',array('size'=>1,'maxlength'=>1)); ?>
<?php //echo $form->error($model,'status'); ?>
</div>
<div class="buttons">
<?php
echo CHtml::ajaxSubmitButton('Submit',CHtml::normalizeUrl(array('Comments/create','render'=>true)),
array(
'dataType'=>'json',
'type'=>'post',
'success'=>'function(data){
$("#AjaxLoader").hide();
if(data.status == "success"){
$("#formResult").html("Comment Submitted");
$("#comments-form")[0].reset();
}else{
$each(data,function(key.val){
$("#comments-form #"+key+"_em_").text(val);
$("#comments-form #"+key+"_em_").show();
});
}
}',
'beforeSend'=>'function(){
$("#AjaxLoader").show();
}'
),array('id'=>'submit','class'=>'btn btn-success'));
?>
<?php $this->endWidget();?>
</div>
请帮帮我......
答案 0 :(得分:0)
确保已注册所有必需的脚本(jQuery等)。在JS控制台中调试它。如果您通过renderPartial方法渲染此表单,则可以在此方法中设置$ processOutput = true param。