Question

我有第一个名为“地方”的实体，用于映射地点数据，如地名，纬度和经度。另一个称为“用户”的实体存储用户数据，如用户名，用户当前纬度，用户当前经度。

我想为“地点”实体添加一个虚拟字段，用于计算地理点之间的距离。

我正在使用此功能 -

class Places{

/**
 * @var integer
 *
 * @ORM\Column(name="id", type="integer")
 * @ORM\Id
 * @ORM\GeneratedValue(strategy="AUTO")
 */
private $id;

/**
 * @var string
 * @ORM\Column(name="name", type="string", length=255)
 * @Assert\NotBlank()
 * @Expose
 */
private $name;

/**
 * @var string
 * @ORM\Column(name="description", type="string", length=255, nullable=true)
 * @Expose
 */
private $description;

/**
 * @var float
 * @ORM\Column(name="lon", type="float", nullable=true)
 * @Expose
 */
private $lon;

/**
 * @var float
 * @ORM\Column(name="lat", type="float", nullable=true)
 * @Expose
 */
private $lat;

/**
 * @var integer
 * @ORM\ManyToOne(targetEntity="Countries")
 * @ORM\JoinColumn(name="country", referencedColumnName="id", onDelete="SET NULL")
 * @Assert\NotBlank()
 * @Expose
 */
private $country;

/**
 * @var string
 * @VirtualProperty
 * @Type("string")
 * @SerializedName("distance")
 * @return string
 */
public function distance(){

    $longitude1 = '34.7722';//$user->getLon();(?)
    $latitude1 = '32.0114';//$user->getLat();(?)
    $longitude2 = $this->getLon();
    $latitude2  = $this->getLat();

    $theta = $longitude1 - $longitude2;
    $miles = (sin(deg2rad($latitude1)) * sin(deg2rad($latitude2))) + (cos(deg2rad($latitude1)) * cos(deg2rad($latitude2)) * cos(deg2rad($theta)));
    $miles = acos($miles);
    $miles = rad2deg($miles);
    $miles = $miles * 60 * 1.1515;
    $kilometers = $miles * 1.609344;
    //return round($kilometers);
    return $this->user->getLastName();
}
}

但是你可以看到lon1 / lat1是硬编码的，因为我无法在places实体中获得用户lan / lat。

我该怎么做？

感谢。

Answer 1

为什么不将场所实体传递给你的函数？

public function distance($place){

  $longitude1 = $place->getLon();
  $latitude1 = $place->getLat();
  $longitude2 = $this->getLon();
  $latitude2  = $this->getLat();

  $theta = $longitude1 - $longitude2;
  $miles = (sin(deg2rad($latitude1)) * sin(deg2rad($latitude2))) + (cos(deg2rad($latitude1)) * cos(deg2rad($latitude2)) * cos(deg2rad($theta)));
  $miles = acos($miles);
  $miles = rad2deg($miles);
  $miles = $miles * 60 * 1.1515;
  $kilometers = $miles * 1.609344;

  return round($kilometers);

}

Answer 2

我懂了!! 使用事件监听器来解决此问题。

监听器：

class SearchIndexer{

        public function __construct(TokenStorageInterface  $tokenStorage)
        {
            $this->tokenStorage = $tokenStorage;
        }

        public function postLoad (LifecycleEventArgs $args){
            $entity = $args->getEntity();
            if ($entity instanceof Places) {
                $user = $this->tokenStorage->getToken()->getUser();
                $entity->setUser_longitude($user->getLastGeoLocationLon());
                $entity->setUser_latitude($user->getLastGeoLocationLat());
            }
        }

    }

服务：

services:
   doctrine.listener:
      class: ApplicationBundle\Listener\SearchIndexer
      arguments: ["@security.token_storage"]
      tags:
          - { name: doctrine.event_listener, event: postLoad }

放置实体：

class Places
{
  private $user_longitude;

        public function setUser_longitude($user_longitude){
            $this->user_longitude = $user_longitude;
        }

        private $user_latitude;

        public function setUser_latitude($user_latitude){
            $this->user_latitude = $user_latitude;
        }

        /**
         * @var string
         * @VirtualProperty
         * @Type("string")
         * @SerializedName("distance")
         * @return string
         */
        public function distance(){

            $longitude2 = $this->getLon();
            $latitude2  = $this->getLat();

            $theta = $this->user_longitude - $longitude2;
            $miles = (sin(deg2rad($this->user_latitude)) * sin(deg2rad($latitude2))) + (cos(deg2rad($this->user_latitude)) * cos(deg2rad($latitude2)) * cos(deg2rad($theta)));
            $miles = acos($miles);
            $miles = rad2deg($miles);
            $miles = $miles * 60 * 1.1515;
            $kilometers = $miles * 1.609344;
            return round($kilometers);

        }
 //rest of the class
}

Answer 3

你在地方和用户之间没有任何关系，你不能在地方实体内做到这一点。假设用户是登录用户。您的逻辑必须在服务中并注入TokenStorage以使用户记录：

namespace Acme\Bundle\AcmeBundle\Manager;

use Symfony\Component\Security\Core\Authentication\Token\Storage\TokenStorageInterface;
use Acme\Bundle\AcmeBundle\Entity\Location;


class LocationFinder{
/*
 * @var TokenStorageInterface
 */
private $tokenStorage;

public function __construct(TokenStorageInterface $tokenStorage)
{
    $this->tokenStorage = $tokenStorage;
}

public function getDistance(Location $location)
{
    $longitude1 =$this->tokenStorage->getToken()->getUser()->getLon();
    $latitude1 = $this->tokenStorage->getToken()->getUser()->getLat();

    $longitude2 = $this->getLon();
    $latitude2  = $this->getLat();

    $theta = $longitude1 - $longitude2;
    $miles = (sin(deg2rad($latitude1)) * sin(deg2rad($latitude2))) + (cos(deg2rad($latitude1)) * cos(deg2rad($latitude2)) * cos(deg2rad($theta)));
    $miles = acos($miles);
    $miles = rad2deg($miles);
    $miles = $miles * 60 * 1.1515;
    $kilometers = $miles * 1.609344;
    return round($kilometers);

}

}

然后你必须在Resources \ config \ services.xml

中创建服务

<?xml version="1.0" ?>

<container xmlns="http://symfony.com/schema/dic/services"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://symfony.com/schema/dic/services http://symfony.com/schema/dic/services/services-1.0.xsd">

<services>
    <service id="acme.manager.location_finder" class="Acme\Bundle\AcmeBundle\Manager\LocationFinder">
        <argument type="service" id="security.token_storage" />
    </service>
</services>
</container>

现在您可以在控制器中获取LocationService并获取位置和用户记录之间的距离

class AccountController extends Controller
{

/**
 * @Route("/place/{id}", name="place")
 * @Method("GET")
 */
public function placeAction($id)
{
    $em = $this->getDoctrine()->getEntityManager();
    $location = $em->getRepository('AcmeBundle:Location')->findOneBy([
        'id' => $id
    ]);
    $distance = $this->get('acme.manager.location_finder')->getDistance($location);
}

}

您有更多信息： http://symfony.com/doc/current/book/service_container.html

Sf2 : using a service inside an entity

symfony实体中的计算/虚拟字段 - 怎么做？

3 个答案: