Question

我有SOAP_SERVICE表，如果新值插入到此表中，那么值也应该插入到SOAP_SERVICE_STATUS表中。我正在写下面的触发器，它没有任何错误并成功编译。但是当我尝试将值插入SOAP_SERVICE表时，该值不会插入到SOAP_SERVICE_STATUS表中。

create or replace TRIGGER RATOR_MONITORING.TRG_TRK_SOAP_SERVICE_STATUS
  AFTER INSERT 
 ON RATOR_MONITORING_CONFIGURATION.SOAP_SERVICE
 FOR EACH ROW
BEGIN
   INSERT INTO RATOR_MONITORING.SOAP_SERVICE_STATUS (SOAP_SERVICE_STATUS_ID,SOAP_SERVICE_ID,STATUS)
       VALUES (SOAP_SERVICE_STATUS_SEQ.nextval,:new.SOAP_SERVICE_ID,'N');
END;

Answer 1

抱歉，无法重现这一个：

SQL> CREATE USER RATOR_MONITORING IDENTIFIED BY "password"
2            DEFAULT TABLESPACE USERS;

User created.

SQL> CREATE USER RATOR_MONITORING_CONFIGURATION IDENTIFIED BY "password"
2            DEFAULT TABLESPACE USERS;

User created.

SQL> GRANT CONNECT TO RATOR_MONITORING, RATOR_MONITORING_CONFIGURATION;

Grant succeeded.

SQL> GRANT CREATE TABLE TO RATOR_MONITORING, RATOR_MONITORING_CONFIGURATION;

Grant succeeded.

SQL> GRANT CREATE SEQUENCE TO RATOR_MONITORING;

Grant succeeded.

SQL> GRANT CREATE ANY TRIGGER TO RATOR_MONITORING;

Grant succeeded.

SQL> ALTER USER RATOR_MONITORING QUOTA UNLIMITED ON USERS;

User altered.

SQL> ALTER USER RATOR_MONITORING_CONFIGURATION QUOTA UNLIMITED ON USERS;

User altered.

SQL> CONNECT RATOR_MONITORING_CONFIGURATION/password
Connected.
SQL> CREATE TABLE RATOR_MONITORING_CONFIGURATION.SOAP_SERVICE (SOAP_SERVICE_ID INTEGER);

Table created.

SQL> CONNECT RATOR_MONITORING/password
Connected.
SQL> CREATE TABLE RATOR_MONITORING.SOAP_SERVICE_STATUS
2              (SOAP_SERVICE_STATUS_ID INTEGER, SOAP_SERVICE_ID INTEGER, STATUS CHAR(1));

Table created.

SQL> CREATE SEQUENCE RATOR_MONITORING.SOAP_SERVICE_STATUS_SEQ;

Sequence created.

SQL> create or replace TRIGGER RATOR_MONITORING.TRG_TRK_SOAP_SERVICE_STATUS
2       AFTER INSERT
3      ON RATOR_MONITORING_CONFIGURATION.SOAP_SERVICE
4      FOR EACH ROW
5     BEGIN
6        INSERT INTO RATOR_MONITORING.SOAP_SERVICE_STATUS (SOAP_SERVICE_STATUS_ID,SOAP_SERVICE_ID,STATUS)
7            VALUES (SOAP_SERVICE_STATUS_SEQ.nextval,:new.SOAP_SERVICE_ID,'N');
8     END;
9     /

Trigger created.

SQL> CONNECT RATOR_MONITORING_CONFIGURATION/password
Connected.
SQL> INSERT INTO RATOR_MONITORING_CONFIGURATION.SOAP_SERVICE (SOAP_SERVICE_ID) VALUES (7);

1 row created.

SQL> COMMIT;

Commit complete.

SQL> CONNECT RATOR_MONITORING/password
Connected.
SQL> SELECT * FROM RATOR_MONITORING.SOAP_SERVICE_STATUS;

SOAP_SERVICE_STATUS_ID SOAP_SERVICE_ID S
---------------------- --------------- -
                     1               7 N

注意：

CREATE ANY TRIGGER权限是RATOR_MONITORING在另一个架构中的表上创建触发器所必需的，
当我们在SQL * Plus中更改连接时，数据库会为我们创建一个新会话供我们使用。在提交这些更改之前，在一个会话中所做的更改在另一个会话中不可见。
SQL * Plus在断开连接时隐式提交事务。在上面的示例中，我们在最后一个CONNECT之前明确提交，以便我们不依赖于隐式行为。

Answer 2

最可能的解释是，您选择具有不同连接的表RATOR_MONITORING.SOAP_SERVICE_STATUS，而无需委托在RATOR_MONITORING_CONFIGURATION.SOAP_SERVICE中执行插入的原始会话。提交后，记录应该是可见的。

另请注意，这是触发器与表不同的模式的副作用;用户RATOR_MONITORING_CONFIGURATION可以在表RATOR_MONITORING.SOAP_SERVICE_STATUS中插入，即使他/她没有INSERT授权！

要启用此功能，用户RATOR_MONITORING必须具有权限create any trigger - 这并不总是被视为最佳做法（强制权限） - 请参阅例如Tom Kyte

Oracle触发器不在另一个表中插入值

2 个答案: