~ $ checksctp
Sctp supported
这是我尝试渲染父母和子女的,但它只是在很多里面循环出当前的页面标题。
任何人都可以帮助我吗?
更新:
<?php
function render_links($page, $level = 0) {
echo "<li>";
echo "<a href=''>" . get_the_title( $page ) . "</a>";
$children = get_pages("child_of=" . $page->id . "&parent=0");
if (!empty($children)) {
echo "<ul>";
foreach ($children as $c) {
render_links($c, $level + 1);
}
echo "</ul>";
}
echo "</li>";
}
echo "<ul>";
foreach (get_pages("parent=0") as $p) {
render_links($top_level);
}
echo "</ul>";
?>
尝试此操作时,它会正确地循环当前页面,然后它会阻止相同的孩子(即使只有1个孩子)。
但是它没有列出网站上的其他父页面。 看图像: https://gyazo.com/93728738fadc3c6e97ed18d20a46d273
渲染后出现此错误:
<?php
function render_links($page, $level = 0) {
echo "<li>";
echo "<a href=''>" . get_the_title( $page ) . "</a>";
$children = get_pages("child_of=" . $page->id);
if (!empty($children)) {
echo "<ul>";
foreach ($children as $c) {
render_links($c, $level + 1);
}
echo "</ul>";
}
echo "</li>";
}
echo "<ul>";
foreach (get_pages("parent=0") as $p) {
render_links($top_level);
}
echo "</ul>";
?>
更新:
Fatal error: Maximum function nesting level of '100' reached, aborting! in C:\wamp\www\yangtorp\wp-includes\cache.php on line
更进一步。现在它列出了父页面,并正确显示了名称。但是我不能让这个工作:
<?php
function render_links($pge, $level = 0) {
echo "<li>";
echo "<a href=''>" . $pge->post_title . "</a>";
$children = get_pages( array( 'child_of' => $post->ID, 'sort_column' => 'post_date', 'sort_order' => 'desc' ) );
if (!empty($children) && $level != 2) {
echo "<ul class='sub-menu'>";
foreach ($children as $c) {
render_links($c, $level + 1);
}
echo "</ul>";
}
else{
echo "</li>";
}
}
echo "<ul id='menu-main' class='menu'>";
foreach (get_pages("parent=0") as $p) {
render_links($p);
}
echo "</ul>";
?>
答案 0 :(得分:2)
我认为你应该这样做:
if (!empty($children)) {
echo "<ul>";
foreach ($children as $c) {
render_links($c, $level + 1);
}
echo "</ul>";
}
//missing else case
else{
echo "</li>";
}
答案 1 :(得分:0)
<?php
function render_links($pge, $level = 0) {
echo "<li>";
echo "<a href=''>" . $pge->post_title . "</a>";
//set arguments for which properties and sorting order the children should get.
$args = array(
'child_of' => $pge->ID,
'parent' => $pge->ID,
'hierarchical' => 0,
'sort_column' => 'menu_order',
'sort_order' => 'asc'
);
// throw the arguments into the get_pages query
$children = get_pages($args);
if (!empty($children) && $level != 2) {
echo "<ul class='sub-menu'>";
foreach ($children as $c) {
render_links($c, $level + 1);
}
echo "</ul>";
}
else{
echo "</li>";
}
}
echo "<ul id='menu-main' class='menu'>";
foreach (get_pages("parent=0") as $p) {
render_links($p);
}
echo "</ul>";
?>