Question

当我在mySQL上运行以下SQL时

SELECT t1.U_COUNT AS U_COUNT, t2.R_COUNT AS R_COUNT 
FROM 
(
SELECT SUM(TRP_COUNT) AS U_COUNT 
FROM `SAL_TAB` 
WHERE CUST='SS' AND TV_POS='VFG' 
) t1,
(
SELECT SUM(TRP_COUNT) AS R_COUNT 
FROM `SAL_TAB` 
WHERE CUST='SS' AND TV_POS='FHT'
) t2;

我得到的输出是

+---------+---------+
| U_COUNT | R_COUNT |
+---------+---------+
|      56 |      67 |
+---------+---------+

我所追求的输出是，

+------------+-------------+
| SALES_TYPE | SALES_COUNT |
+------------+-------------+
| U_COUNT    |          56 |
| R_COUNT    |          67 |
+------------+-------------+

我花了很多时间试图解决这个问题，但却未能做到。有人可以帮我吗？

Answer 1

试试这个

var collection = [
{
     name:"John",
     age:12,
     location:"Califonia",
     gender:"Male"
},
{
     name:"Jane",
     age:18,
     location:"New york",
     gender:"Female"
}
]

function getMaxKeys(collection){
        var keys = Object.keys(collection[0]);
        var keyWithMaxWidth = keys.reduce(function(prev, current){
            if(prev.length > current.length) return prev;
            else return current
        });
        return keyWithMaxWidth;
}

getMaxKeys(collection) //location

MySQL - 使用除列名称之外的其他标题显示一个在另一个之下的输出列

1 个答案: