菜单项在片段android中调用两次

时间:2015-08-31 06:35:03

标签: android menu android-actionbar fragment double-click

In fragment when i click on menu item , it calls function twice one is from previous fragment and other one is from existing fragment.

Fragment 1:
     @Override
        public void onActivityCreated(Bundle savedInstanceState) {
            super.onActivityCreated(savedInstanceState);
            setHasOptionsMenu(true);
        }
        @Override
        public boolean onOptionsItemSelected(MenuItem item) {
            if(item.getItemId() == R.id.refresh){
                RetryCallMap();
                return true;
            }else
            return false;
        }
Fragment 2:
     @Override
        public void onActivityCreated(Bundle savedInstanceState) {
            super.onActivityCreated(savedInstanceState);
            setHasOptionsMenu(true);
        }
        @Override
        public boolean onOptionsItemSelected(MenuItem item) {
            if(item.getItemId() == R.id.refresh){
                RetryCall();
                return true;
            }else
            return false;
        }
MainActivity :

    @Override
        public boolean onCreateOptionsMenu(Menu menu) {
            getMenuInflater().inflate(R.menu.menu_main, menu);
            return true;
        }

        @Override
        public boolean onOptionsItemSelected(MenuItem item) {
            int id = item.getItemId();
            if (id == R.id.map) {
                pushFragments("mapFragment", new MapFragment(), true, true);
                return true;
            }
            if (id == android.R.id.home) {
                this.drawerLayout.openDrawer(drawableListView);
                return true;
            }
            return super.onOptionsItemSelected(item);
        }

这些片段和我的MainActivity我通过单击菜单项来刷新片段,这样如果找不到互联网连接或者在获取i时出现任何其他问题,则可以刷新页面。

1 个答案:

答案 0 :(得分:0)

在onOptionsItemSelected()函数中返回true对我有用。

 @Override
    public boolean onOptionsItemSelected(MenuItem item) {
        if(item.getItemId() == R.id.refresh){
            RetryCall();
            return true;
        }else
        return true;
    }