Question

我有两个表t1和t2（t1的大小为t2的1/10）。每个表都有两列<Lat, Long>，其中包含某些点的纬度和经度。对于t1中的每一行，我想在t2中找到最接近它的行。这样做最有效的查询是什么？ Hive是否有任何类型的地理空间搜索库？

Answer 1

你需要做一点触发。

请参阅Database Journal

上的这篇文章

我相信的最后一个例程就是你要找的东西（你需要修改它以供你使用）：

CREATE DEFINER=`root`@`localhost` PROCEDURE closest_restaurants_optimized`
(IN units varchar(5), IN lat Decimal(9,6), IN lon Decimal(9,6), 
IN max_distance SMALLINT, IN limit_rows MEDIUMINT)
BEGIN
    DECLARE ONE_DEGREE_CONSTANT TINYINT;
    DECLARE EARTH_RADIUS_CONSTANT SMALLINT;
    DECLARE lon1, lon2, lat1, lat2 float;  
    IF units = 'miles' THEN
        SET ONE_DEGREE_CONSTANT   = 69;
        SET EARTH_RADIUS_CONSTANT = 3959;
    ELSE -- default to kilometers
        SET ONE_DEGREE_CONSTANT   = 111;
        SET EARTH_RADIUS_CONSTANT = 6371;
    END IF;  
    SET lon1 = lon-max_distance/abs(cos(radians(lat))*ONE_DEGREE_CONSTANT);
    SET lon2 = lon+max_distance/abs(cos(radians(lat))*ONE_DEGREE_CONSTANT);
    SET lat1 = lat-(max_distance/ONE_DEGREE_CONSTANT);
    SET lat2 = lat+(max_distance/ONE_DEGREE_CONSTANT);
    SELECT pm1.post_id, p.post_title,
        ROUND((EARTH_RADIUS_CONSTANT * acos( cos( radians(lat) ) 
            * cos( radians(pm1.meta_value) ) 
            * cos( radians(pm2.meta_value) - radians(lon)) + sin(radians(lat)) 
            * sin( radians(pm1.meta_value)))
        ), 3) AS distance
    FROM goodfood_wp_md20m_postmeta AS pm1, 
        goodfood_wp_md20m_postmeta AS pm2,
        goodfood_wp_md20m_posts    AS p 
    WHERE pm1.meta_key = 'latitude' AND pm2.meta_key = 'longitude'
    AND pm1.post_id = pm2.post_id
    AND pm1.post_id = p.id
    AND p.post_status = 'publish'
    AND pm2.meta_value between lon1 and lon2 
    AND pm1.meta_value between lat1 and lat2
    ORDER BY distance ASC
    LIMIT limit_rows;
END

找到最接近lat和long值的位置

1 个答案: