Question

我正在使用以下json在Parse中发送推送通知。

{
  "alert": "Push title goes here",
  "sound": "",
  "url": "emap://video/4000"
}

如果我在Safari中输入并点击输入，则网址emap://video/4000指向应用内的特定视频。我希望用户在点击通知时发送到此视频。为什么上面的JSON没有达到这个目的？

Answer 1

所以说我们发送这个有效载荷：

NSDictionary *data = @{
    @"alert" : @"some generic message here",
    @"badge" : @"Increment",
    @"sound" : @"default",
    @"url" : @"emap://video/4000"
};

当用户与之互动时，请采取相应行动：

- (void)application:(UIApplication *)application didReceiveRemoteNotification:(NSDictionary *)userInfo {

    if (application.applicationState == UIApplicationStateInactive) {
      [self handleRemoteNotificationWithPayload:userInfo];
    }
}

-(void)handleRemoteNotificationWithPayload:(NSDictionary *)payload {

    if (payload) {
       NSString *urlLink = [payload valueForKey:@"url"];
       // perform segue or tab bar selectedIndex or open webView whatever you want after checking if user is launching from notification :
    }
}

如果用户应用已被终止或从内存中释放，您也应该在application didFinishLaunchingWithOptions:中调用此内容：

- (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions {
...
    NSDictionary *notificationPayload = launchOptions[UIApplicationLaunchOptionsRemoteNotificationKey];
    [self handleRemoteNotificationWithPayload:notificationPayload];
...
}

解析通知：如何使用自定义有效负载

1 个答案: