Kivy文件

Question

是否可以使用python中的屏幕对象来引用屏幕管理器？基本上我想从python中更改屏幕。

在kivy中很简单：

app.root.current='ScreenName'

我不想在这里创建一个新的屏幕管理器对象。

我这样做是因为在kivy语言中我使用此代码：

on_release: root.select_experiment();app.root.current= 'StartExperiment'

root.select_experiment()调用pop。我希望只有在弹出窗口被取消后才能转换到StartExperiment屏幕。从kivy开始，它发生在之前。编辑：

 Traceback (most recent call last):
   File "C:\Users\sony\Desktop\test\main.py", line 171, in <module>
     AppBaseClass().run()
   File "C:\Anaconda\lib\site-packages\kivy\app.py", line 824, in run
     runTouchApp()
   File "C:\Anaconda\lib\site-packages\kivy\base.py", line 487, in runTouchApp
     EventLoop.window.mainloop()
   File "C:\Anaconda\lib\site-packages\kivy\core\window\window_sdl2.py", line 525, in mainloop
     self._mainloop()
   File "C:\Anaconda\lib\site-packages\kivy\core\window\window_sdl2.py", line 290, in _mainloop
     EventLoop.idle()
   File "C:\Anaconda\lib\site-packages\kivy\base.py", line 330, in idle
     self.dispatch_input()
   File "C:\Anaconda\lib\site-packages\kivy\base.py", line 315, in dispatch_input
     post_dispatch_input(*pop(0))
   File "C:\Anaconda\lib\site-packages\kivy\base.py", line 281, in post_dispatch_input
     wid.dispatch('on_touch_up', me)
   File "kivy\_event.pyx", line 699, in kivy._event.EventDispatcher.dispatch (kivy\_event.c:7011)
   File "C:\Anaconda\lib\site-packages\kivy\uix\behaviors.py", line 163, in on_touch_up
     self.dispatch('on_release')
   File "kivy\_event.pyx", line 695, in kivy._event.EventDispatcher.dispatch (kivy\_event.c:6970)
   File "kivy\_event.pyx", line 1168, in kivy._event.EventObservers.dispatch (kivy\_event.c:12154)
   File "kivy\_event.pyx", line 1092, in kivy._event.EventObservers._dispatch (kivy\_event.c:11729)
   File "C:\Users\sony\Desktop\test\main.py", line 84, in file_button_clicked
     self.parent.ids.MyScreenManager.current = 'StartExperiment'
   File "kivy\properties.pyx", line 720, in kivy.properties.ObservableDict.__getattr__ (kivy\properties.c:10911)
 AttributeError: 'super' object has no attribute '__getattr__'

Answer 1

我认为最简单的方法是给屏幕管理员一个用kivy语言编写的ID，然后从Python中引用该ID。

Kivy文件

ScreenManager:
    id: MyScreenManager

的Python

self.parent.current = 'Target_Screen'

参考屏幕管理器

1 个答案:

Kivy文件

的Python