Question

我正在尝试创建一个登录页面来演示一个简单的SQL注入攻击。下面是从login.html接收输入的php代码：

<?php 
define('DB_HOST', 'localhost'); 
define('DB_NAME', 'sql-injection'); 
define('DB_USER','root'); 
define('DB_PASSWORD',''); 
$con=@mysql_connect(DB_HOST,DB_USER,DB_PASSWORD) or die("Failed to connect to MySQL: " . mysql_error()); 
$db=mysql_select_db(DB_NAME,$con) or die("Failed to connect to MySQL: " . mysql_error()); 
/* $ID = $_POST['user']; $Password = $_POST['pass']; */ 

function SignIn() 
{ 
session_start(); //starting the session for user profile page 

if(!empty($_POST['user']) and !empty($_POST['pass'])) //checking the username and password which is coming from Sign-In.html, are they empty or have some text
 {      

        $query = mysql_query("SELECT * FROM UserName where userName = '$_POST[user]'") or die(mysql_error()); 

        $row = mysql_fetch_array($query) or die(mysql_error()); 

        if(!empty($row['userName']) AND !empty($row['pass'])) 
        { 
                if ($_POST['pass'] == $row['pass'])
                {
                    echo "SUCCESSFULLY LOGIN TO USER PROFILE PAGE...";
                }
                else
                {
                    echo "SORRY... YOU ENTERD WRONG ID AND PASSWORD... PLEASE RETRY..."; 
                }

        } 
        else 
        {   
                    echo "The db is corrupt";
        } 
} 
else{
    echo "The username and password fields cant be empty";
}
} 
if(isset($_POST['submit'])) 
{ 

SignIn(); 

} 

?>

db有一个表用户名，列

UsernameID userName   pass
1          mrboolnew  mrbool123

我想在用户名栏中输入：

Y'; UPDATE username SET userName ='mrboolnew1'WHERERE userName ='mrboolnew';

但我得到以下错误：

您的SQL语法有错误;查看与您的MySQL服务器版本对应的手册，以便在'UPDATE username SET userName ='mrboolnew1'附近使用正确的语法'WHERE userName ='mrboolnew';''在第1行

有人可以帮我解决注射问题。提前谢谢。

Answer 1

您已添加了防止注入攻击的保护，可能甚至不知道。mysql_query()只向数据库发送一个查询（请参阅here）。不允许使用分号;也不是多个查询。

您必须更加努力地注入自己的代码。

创建sql注入的演示时出现sql语法错误

1 个答案: