Question

我想在这种Array / Tuple / Dictionary public static void main(String[] args) { System.out.println(duplicates("aabbbbbb976fkkkkc", '\0')); }中添加en条目：

data

for循环正在改变＆＃34;键＆＃34;对Int的任何元素的元组。我希望Tuple也把密钥作为字典。

var i=0
var data = [("foo", ["first": 1, "second": 2]), ("bar", ["first": 1, "second": 2])] 
var newData = [(Int, [String: AnyObject])]()
for (key, value) in data {

    newData.append((i, value))

    i = i+1
}

变成

[("foo", ["first": 1, "second": 2]),
 ("bar", ["first": 1, "second": 2])]

我想要的是：

 [(1, ["first": 1, "second": 2]), 
  (2, ["first": 1, "second": 2])]

Answer 1

从

开始

let data: [(String, [String: AnyObject])] = [
    ("foo", ["first": 1, "second": 2]),
    ("bar", ["first": 1, "second": 2])]

这是一种不需要单独计数变量的变种

let newData = data.map({ (var e) -> [String: AnyObject] in
    e.1.updateValue(e.0, forKey: "key")
    return e.1
}).enumerate().map({ ($0.0 + 1, $0.1) })

enumerate调用也可以移到前面，这使得块签名不那么紧凑。

let newData = data.enumerate().map { (var e) -> ((Int, [String: AnyObject])) in
    e.1.1.updateValue(e.1.0 , forKey: "key")
    return (e.0 + 1, e.1.1)
}

两种变体都会导致

[(1, ["first": 1, "second": 2, "key": "foo"]),
 (2, ["first": 1, "second": 2, "key": "bar"])]

Answer 2

试试这个

var data = [("foo", ["first": 1, "second": 2]), ("bar", ["first": 1, "second": 2])]

var i = 0
var newData = [(Int, [String: AnyObject])]()
for (key, value) in data {

  var newValue : [String:AnyObject] = value
  newValue["key"] = key
  newData.append((++i, newValue))
}

print(newData)

或使用Swift map函数

var i = 0
let newData = data.map { (key, value) -> (Int, [String: AnyObject]) in
  var newValue = value
  newValue["key"] = key
  return (++i, newValue)
}

print(newData)

Swift - 如何添加展开嵌套字典？

2 个答案: