Question

我有以下XML：

<funds>
    <fund name="A" ITEM0="7%" ITEM1="8%" ITEM2="9%" ITEM3="10%" ITEM4="11%" ITEM5="" /> 
    <fund name="B" ITEM0="11%" ITEM1="11%" ITEM2="13%" ITEM3="14%" ITEM4="16%" ITEM5="" /> 
    <fund name="C" ITEM0="" ITEM1="" ITEM2="" ITEM3="" ITEM4="" ITEM5="" /> 
    <fund name="D" ITEM0="7%" ITEM1="8%" ITEM2="9%" ITEM3="10%" ITEM4="11%" ITEM5="" /> 
    <fund name="E" ITEM0="2%" ITEM1="3%" ITEM2="3%" ITEM3="5%" ITEM4="5%" ITEM5="" /> 
    <fund name="F" ITEM0="" ITEM1="" ITEM2="" ITEM3="" ITEM4="" ITEM5="" /> 
    <fund name="G" ITEM0="3%" ITEM1="3%" ITEM2="3%" ITEM3="5%" ITEM4="5%" ITEM5="" /> 
</funds>
<ToAppend>
    <append name="A" ITEM="10" />
    <append name="B" ITEM="15" />
    <append name="C" ITEM="20" />
    <append name="D" ITEM="20" />
    <append name="E" ITEM="15" />
    <append name="F" ITEM="10" />
    <append name="G" ITEM="10" />
</ToAppend>

如何循环// ToAppend / append中的所有属性，如果'name'与//基金/基金相匹配，请添加来自// ToAppend / append to // funds / fund的属性ITEM？< / p>

我正在尝试将匹配的项目附加到第一个列表，但我没有太多运气。试图在2.0框架下通过C＃实现这一点。

提前致谢！

编辑：

XmlNode xmlNodeInner = root.SelectSingleNode("//ToAppend/append");
XmlNode ToBeUpdated = root.SelectSingleNode("//funds/fund");

foreach (XmlElement element in ToBeUpdated)
    {
        Console.WriteLine(element.InnerXml);
       //Match the 'name' from xmlNodeInner to the 'name' of ToBeUpdated
       //if{magic occurs here and they match}
        {
            element.SetAttribute("ITEM6", "value from xmlNodeInner");
       }
    }

我只是不知道如何进行比较查询以确定A = A，甚至是否存在，因为没有保证。希望它会出现像：

<fund name="G" ITEM0="3%" ITEM1="3%" ITEM2="3%" ITEM3="5%" ITEM4="5%" ITEM5="" ITEM6="10"/>

Answer 1

这似乎有效：

namespace ConsoleApplication1
{
    using System;
    using System.Xml;

    class Program
    {
        static void Main( string[] args )
        {
            const string xml = @"
<root>
    <funds>
        <fund name='A' ITEM0='7%' ITEM1='8%' ITEM2='9%' ITEM3='10%' ITEM4='11%' ITEM5='' /> 
        <fund name='B' ITEM0='11%' ITEM1='11%' ITEM2='13%' ITEM3='14%' ITEM4='16%' ITEM5='' /> 
        <fund name='C' ITEM0='' ITEM1='' ITEM2='' ITEM3='' ITEM4='' ITEM5='' /> 
        <fund name='D' ITEM0='7%' ITEM1='8%' ITEM2='9%' ITEM3='10%' ITEM4='11%' ITEM5='' /> 
        <fund name='E' ITEM0='2%' ITEM1='3%' ITEM2='3%' ITEM3='5%' ITEM4='5%' ITEM5='' /> 
        <fund name='F' ITEM0='' ITEM1='' ITEM2='' ITEM3='' ITEM4='' ITEM5='' /> 
        <fund name='G' ITEM0='3%' ITEM1='3%' ITEM2='3%' ITEM3='5%' ITEM4='5%' ITEM5='' /> 
    </funds>
    <ToAppend>
        <append name='A' ITEM='10' />
        <append name='B' ITEM='15' />
        <append name='C' ITEM='20' />
        <append name='D' ITEM='20' />
        <append name='E' ITEM='15' />
        <append name='F' ITEM='10' />
        <append name='G' ITEM='10' />
    </ToAppend>
</root>
";
            // XPath that finds all "funds/fund" nodes that have a "name" attribute with the value "{0}".
            const string xpathTarget = @"//funds/fund[@name='{0}']";

            // XPath that finds all "ToAppend/append" nodes that have a "name" and "ITEM" attribute.
            const string xpathSourceNodes = @"//ToAppend/append[@name and @ITEM]";

            var doc = new XmlDocument();
            doc.LoadXml( xml );

            foreach ( XmlNode sourceNode in doc.SelectNodes( xpathSourceNodes ) )
            {
                string name = sourceNode.Attributes[ "name" ].Value;
                string item = sourceNode.Attributes[ "ITEM" ].Value;

                XmlNode targetNode = doc.SelectSingleNode( String.Format( xpathTarget, name ) );

                if ( null != targetNode )
                {
                    XmlAttribute newAttribute = doc.CreateAttribute( "ITEM6" );
                    newAttribute.Value = item;

                    targetNode.Attributes.Append( newAttribute );
                }
            }
        }
    }
}

如何根据其他属性向XML节点添加属性？

1 个答案: