Question

这是xml

public class TrackingService extends Service implements AsyncTaskCallback,
        LocationListener {
    LocationManager lm;
    @Override
    public int onStartCommand(Intent intent, int flags, int startId) {
        detectLocation();
        return START_STICKY;
    }
    private void detectLocation() {
        // TODO Auto-generated method stub
        Toast.makeText(this, "Inside detectlocation()", Toast.LENGTH_SHORT)
                .show();
        lm = (LocationManager) getSystemService(Context.LOCATION_SERVICE);
        lm.requestLocationUpdates(LocationManager.GPS_PROVIDER, 30 * 1000, 0,
                this);
        enableGPS(lm);

    }
    @Override
    public void onDestroy() {
        super.onDestroy();
        lm.removeUpdates(this);
        System.out.println("ABC locationManager is not equal null.");       
    }

    public void stopTrackingService(){
        lm.removeUpdates(this);
    }
}

我需要阅读此xml文件并创建一个包含

的列表

public class Map extends FragmentActivity implements OnMapReadyCallback, ConnectionCallbacks, OnConnectionFailedListener{
    @Override
    protected void onDestroy() {
        super.onDestroy();
 // To stop the service when the user closed the app in the background and the map ativity was opened.      
        stopAlarm();
        Intent i = new Intent(this, TrackingService.class);
        stopService(i);
        System.out.println("ABC Map onDestroy() was invoked!");

    }

}

简单快捷的方法是什么？

Answer 1

您可以使用LinqToXml

var list = XDocument.Load(filename)
           .Descendants("Result")
           .Select(x => (string)x)
           .ToList();

Answer 2

使用XML阅读器和编解码器将DOM树转换为列表。

如何从简单的xml文件创建列表<string>？

2 个答案: