Question

create table #temp
    (
    TREE varchar (500), 
    SEED varchar (500), 
    FLOWER  varchar (500),
    Year    varchar (500),
    FLRNO   varchar (500),
    COMMENT1 varchar (500),
    COMMENT3 varchar (500),
    hash AS hashbytes('MD5', [TREE] +  SEED +  FLOWER + YEAR + FLRNO +      
COMMENT1 + COMMENT3)

    )


    insert #temp

    SELECT 'BANANA',    'Nis',  'Tit',  '2004', '57101',    'Sweet Smell     
Flower',  '' UNION ALL
    SELECT 'BANANA',    'Nis',  'Tit',  '2004', '57101',    'Bad Smell 
flower' ,  '' UNION ALL
    SELECT 'BANANA',    'Nis',  'Tit',  '2004', 'B0019B',   'Sweet Smell 
Flower',  'CATCH ME' UNION ALL
    SELECT 'BANANA',    'Nis',  'Tit',  '2004', 'B0019B',   'Bad Smell 
flower',       'CATCH ME' UNION ALL
    SELECT 'APPLE',     'ALE',  'PPL',  '2015', 'PRS13',    'SXT; SWEET 
SMELL FLOWER',  'God' UNION ALL
    SELECT 'APPLE',     'ALE',  'PPL',  '2015', 'PRS13',    'SE; Bad SMELL 
FLOWER',    'CATCH ME' UNION ALL
    SELECT 'APPLE',     'ALE',  'PPL',  '2015', 'PRS13',    'SXT; SWEET 
SMELL FLOWER',  'CATCH ME'

我们如何检查TREE，SEED，FLOWER和Year组是否存在FLRNO，该组存在于组中的所有可用COMMENT1 和同一组TREE，SEED，FLOWER和Year都有评论3，其中包含所有可用的COMMENT1

树APPLE上帝不适用于＆＃34; SE;坏SMELL FLOWER＆＃34;所以整个组都从输出中排除。

预期产出： / *

 'BANANA',  'Nis',  'Tit',  '2004', '57101',    'Sweet Smell Flower',  '' 
'BANANA',   'Nis',  'Tit',  '2004', '57101',    'Bad Smell flower'  ,  '' 
 'BANANA',  'Nis',  'Tit',  '2004', 'B0019B',   'Sweet Smell Flower',      
'CATCH ME' 
 'BANANA',  'Nis',  'Tit',  '2004', 'B0019B',   'Bad Smell flower',    'CATCH ME'

* /

- 已尝试查询但未提供结果

; WITH CTE AS (
   SELECT [TREE], SEED, FLOWER, YEAR,
          COUNT(DISTINCT hash) AS grp_count,
          --COUNT(*) AS grp_count,
          COUNT(DISTINCT FLRNO) AS part_grp_count,
          COUNT(DISTINCT COMMENT1) AS COMMENT1_grp_count,
          COUNT(DISTINCT COMMENT3)AS COMMENT3_grp_count
   FROM   #temp
   GROUP  BY [TREE], SEED, FLOWER, YEAR
)
SELECT *
FROM   #temp t
WHERE  EXISTS (SELECT *
               FROM   CTE
               WHERE  CTE.[TREE] = t.[TREE]
                 AND  CTE.FLOWER = t.FLOWER
                 AND  CTE.SEED = t.SEED
                 AND  CTE.YEAR = t.YEAR
                 AND  CTE.grp_count = CTE.COMMENT1_grp_count * CTE.COMMENT3_grp_count * CTE.part_grp_count
                 AND  CTE.COMMENT1_grp_count > 1)

Answer 1

目前还不清楚你想要完成什么，但至少这会得到你的结果：

select * from temp t
where 
  (
    select top 1 count(distinct comment1)
    from temp t2
    where t2.tree = t.tree
    group by t2.comment3
    order by 1 asc
  ) > 1

SQL Fiddle

中的示例

T-SQL中的多个分组

1 个答案: