Question

我有一个应用程序，我需要移动堆栈的按钮（就像将一堆卡片的一部分从一堆移动到另一堆）。我已经在xml布局中定义了所有按钮，并为所有人设置了触摸和拖动侦听器。我可以单独拖放屏幕周围的任何按钮。但在某些情况下我需要做的是拖动堆叠在我同时点击的原始按钮顶部的其他按钮。有没有办法“欺骗”或模拟按下另一个按钮（所以听众注册它）？谢谢 ***编辑于2015年9月8日 @覆盖 public boolean onTouch（View v，MotionEvent e）{ // tosty（“mclicking：”+ mClicking）; int startpos = 0; switch（e.getAction（）＆amp; MotionEvent.ACTION_MASK）{

    case MotionEvent.ACTION_DOWN:

        isWastePile=false;

        get_selected_deck(v); // determines which of 7 decks or layouts in the tablau you have
                                // clicked
        FromDeck = selecteddeck;
        FromDeckCard = deckcard;
        FromDeckButton = deckbutton;
        // if (!mClicking) {
        mClicking = true;
        //String piecetag = (String) v.getTag();

        // // IDEA!!!/ ///
        /*
         * I wrote a function that finds all the ImageButtons below where
         * the user clicked, and set them all to invisible. I then created a
         * new Linear Layout within the Linear Layout that the user clicked (during the ACTION_DOWN event),
         * and passed that into the Drag Shadow builder during the ACTION_MOVE event.
         * 
         * Once into the ACTION_DROP portion, I simply referenced global
         * variables to figure out if the user dropped in one or multiple
         * ImageButtons, and dealt with them accordingly.
         */

        //if (!isWastePile) {
        //draglayout.setClipChildren(false);
        lltemp = new LinearLayout(this);
        lltemp.setOrientation(LinearLayout.VERTICAL);
        LinearLayout.LayoutParams llparams = new LinearLayout.LayoutParams(
                LayoutParams.WRAP_CONTENT, LayoutParams.WRAP_CONTENT);

        llparams.setMargins(0, -52, 0, 0);
        lltemp.setLayoutParams(llparams);
        draglayout.addView(lltemp);


        for (int i = 0; i < deckstack_list[selecteddeck].size(); i++) {
            if (v == (draglayout.getChildAt(i))) {
                startpos = i;
                for (int o = i; o < deckstack_list[selecteddeck].size(); o++) {
                    // layout5.removeViewAt(o);
                    draglayout.getChildAt(o).setVisibility(View.GONE); // all
                                                                            // buttons
                                                                            // being
                    dragtempstack.push((Integer) deckstack_list[selecteddeck].get(o))   ;                                                   // dragged
                                                                            // to
                                                                            // invisible
                    // then recreate another linear layout within layout5
                    // and pass to dragshadow builder
                    // to do

                    // also set a GLOBAL variable with stack count (number
                    // of cards dragged)
                    lltemp.setClipChildren(false);
                    lltemp.addView(createtempButtons(o, startpos));


                }

            }
        }
        //} // end if wastepile check statement

        //tosty("dragtempstack size: "+dragtempstack.size());

        break;

    case MotionEvent.ACTION_MOVE:

        //tosty("Action MOVE");
        Log.i("ACTION Event: ", "ACTION MOVE");
        // v = layout5;


        v = lltemp;


        v.setVisibility(View.INVISIBLE);
        v.bringToFront();
        v.invalidate();
        v.setVisibility(View.VISIBLE);

        //DragShadowBuilder shadowBuilder = new View.DragShadowBuilder(v);
        DeckDragShadow shadowBuilder = new DeckDragShadow(v);
        v.startDrag(null, shadowBuilder, v, 0);


        correctDrag = false;

        break;

    private Button createtempButtons(final int i, final int startpos) {
    final Button b = new Button(this);

    b.setOnTouchListener(this);
    b.setOnDragListener(new DeckDragListener());

    b.setBackgroundResource(cardimagearray[dragdeckstack.get(i)]);

    float width = TypedValue.applyDimension(TypedValue.COMPLEX_UNIT_DIP,
            45, getResources().getDisplayMetrics());
    float height = TypedValue.applyDimension(TypedValue.COMPLEX_UNIT_DIP,
            61, getResources().getDisplayMetrics());

    LinearLayout.LayoutParams params = new LinearLayout.LayoutParams(
            (int) width, (int) height);
    float margTop = TypedValue.applyDimension(TypedValue.COMPLEX_UNIT_DIP,
            -36, getResources().getDisplayMetrics());

    if (i > startpos) {
        params.setMargins(0, -57, 0, 0);
    }

    b.setLayoutParams(params);

    // b.bringToFront();
    // b.invalidate();
    b.setVisibility(View.VISIBLE);

    return b;

Answer 1

我不会尝试复制每个按钮的侦听器，而是将按钮视为组。当您单击组中的按钮时，它会分为两组：按钮上方有按钮以及您要留下的内容。然后将该组拖放到其他组中。

如Templerschaf建议的那样，这些群组可能是LinearLayouts：

您点击LinearLayout
注册哪个项目
使包含该项目下方的项目的新LinearLayout位于正确的位置
删除所点击项目下方的项目并相应调整大小
然后可以继续拖动布局
然后可以将其放在另一个LinearLayout上，这会将项目添加到自己的列表中

这与ListView动画非常相似。参见：

https://www.youtube.com/watch?v=_BZIvjMgH-Q

https://www.youtube.com/watch?v=mwE61B56pVQ

https://github.com/bauerca/drag-sort-listview/blob/master/library/src/com/mobeta/android/dslv/DragSortListView.java

在java中拖动多个按钮视图

1 个答案: