Question

如何搜索我有这种类型的数组这是数组的一个对象

@interface Recipe : NSObject

@property (nonatomic, strong) NSString* recipeName;
@property (nonatomic, strong) NSString* recipeId;
@property (nonatomic, retain) NSString* rcpDescription;
@property (nonatomic, retain) NSString* servingSize;
@property (nonatomic, retain) NSString* totalCalories;

这里我从tableview

中的数组数据设置recipename

Recipe* aRecipe = [recipeAry objectAtIndex:indexPath.row];
    cell.lbl_name = aRecipe.recipeName

问题是当我使用NSPredicate时无法搜索到这里是我的代码请给我解决方案

NSPredicate *predicate = [NSPredicate predicateWithFormat:@"SELF.recipeName= %@", searchText];
       // SELF.shipBuilder LIKE[cd] %@

        self.searchData = [recipeAry filteredArrayUsingPredicate:predicate];
        NSLog(@"%@",self.searchData);

Answer 1

尝试使用％K

＆＃xA;＆＃xA;

  NSPredicate * filterPredicate = [NSPredicate predicateWithFormat：@“％K包含[cd]”， recipeName，searchText];＆＃xA;

＆＃xA;

Answer 2

使用以下代码过滤来自 Recipe 对象的给定数组的结果

NSArray *recipeAry; //your data array

//create a search predicate to filter the array
NSPredicate *searchPredicate = [NSPredicate predicateWithBlock:^BOOL(Recipe *evaluatedObject, NSDictionary *bindings) {

    return [evaluatedObject.recipeName hasPrefix:searchText];
}];

self.searchData = [recipeAry filteredArrayUsingPredicate:searchPredicate]; //this is the filtered array you can use for the displaying UI with search results.

ios NSPredicate在数组对象中搜索

2 个答案: