Question

我正在尝试修剪电话号码并使用以下代码，但它不会修剪空格或“ - ”。我需要擦除所有字符，除了字符集中的字符

 func trimmedNumber(s : String)->String
 {
    let characterSet = NSCharacterSet(charactersInString: "+*#0123456789")
   let trimmedString =  s.stringByTrimmingCharactersInSet(characterSet.invertedSet)
    return trimmedString
}

Answer 1

Swift 3/4：

let set = CharacterSet(charactersIn: "+*#0123456789")
let stripped = s.components(separatedBy: set.inverted).joined()

Answer 2

func trimmedNumber(s : String) -> String {
  let characterSet = Set("+*#0123456789".characters)
  return String(s.characters.lazy.filter(characterSet.contains))
}

或者在Swift 1中：

func trimmedNumber(s : String) -> String {
  let characterSet = Set("+*#0123456789")
  return String(lazy(s).filter { characterSet.contains($0) })
}

Answer 3

适用于swift 1＆amp; 2

    let s = "adasdad+3124124+r323*4asdasdbk*($&#@"

    let characterSet = NSCharacterSet(charactersInString: "+*#0123456789").invertedSet;
    let elements = s.componentsSeparatedByCharactersInSet(characterSet)
    let filtered = (elements as NSArray).componentsJoinedByString("")

    print(filtered);

Answer 4

将方法removingCharacters(in:)添加到Swift的String类型。它返回一个新字符串，该字符串是通过从String中删除给定字符集中的字符而生成的。

例如：

let string = "+1-202-555-0141"
let set = CharacterSet(charactersIn: "+*#0123456789")
let sanitized = string.removingCharacters(in: set.inverted)
// sanitized is equal to "+12025550141"

Helpers.swift

extension String {
    public func removingCharacters(in set: CharacterSet) -> String {
        let filtered = unicodeScalars.lazy.filter { !set.contains($0) }
        return String(String.UnicodeScalarView(filtered))
    }
}

HelpersTests.swift

import XCTest

class HelpersTests: XCTestCase {
    func testRemovingCharacters() {
        let inputText1 = ""
        let set1 = CharacterSet.decimalDigits.inverted
        let sanitized1 = inputText1.removingCharacters(in: set1)
        XCTAssertEqual("", sanitized1)

        let inputText2 = " tab:\tspace: no-break_space: "
        let set2 = CharacterSet.whitespaces
        let sanitized2 = inputText2.removingCharacters(in: set2)
        XCTAssertEqual("tab:space:no-break_space:", sanitized2)

        let inputText3 = " aBc!@#12 $%^&*()-_=+[{]}\\|;:'\"3,<.>/?`~ "
        let set3 = CharacterSet.alphanumerics.inverted
        let sanitized3 = inputText3.removingCharacters(in: set3)
        XCTAssertEqual("aBc123", sanitized3)
    }
}

另请参阅：Convert Array of UnicodeScalar into String in Swift

如何删除除Swift中的CharacterSet之外的所有字符

4 个答案: