Question

使用以下代码，我在尝试发出信号时收到错误（'PySide.QtCore.Signal' object has no attribute 'emit'）：

#!/usr/bin/env python

from PySide import QtCore

class TestSignalClass(QtCore.QObject):
    somesignal = QtCore.Signal()

    def speak_me(self):
        self.speak.emit()
    def __init__(self):
        try:
            self.somesignal.emit()
        except Exception as e:
            print("__init__:")
            print(e)

t = TestSignalClass()

我该怎么做才能解决这个问题？

Answer 1

这里的问题是虽然类正确地继承自QtCore.QObject，但它不会调用父的构造函数。这个版本工作正常：

#!/usr/bin/env python

from PySide import QtCore

class TestSignalClass(QtCore.QObject):
    somesignal = QtCore.Signal()

    def speak_me(self):
        self.speak.emit()
    def __init__(self):
        # Don't forget super(...)!
        super(TestSignalClass, self).__init__()
        try:
            self.somesignal.emit()
        except Exception as e:
            print("__init__:")
            print(e)

t = TestSignalClass()

Answer 2

上面的解决方案对我来说是“奇怪” ...因此，我在下面提供了我的解决方案...

from PySide2.QtCore import Signal, QObject

class myTestObject(QObject):
    someSignal = Signal(str)

    def __init__(self):
        QObject.__init__(self)  # call to initialize properly
        self.someSignal.connect(self.testSignal)  # test connect
        self.someSignal.emit("Wowz")  # test

    def testSignal(self, arg):
        print("my signal test from init fire", arg)

PySide：'PySide.QtCore.Signal'对象没有属性'emit'

2 个答案: