Question

我有一个tkinter应用程序，我已经在课程中创建了它。

第一个是class MainWindow()，主窗口正在绘制。另一个是class SettingsWindow()，其中选项窗口正在绘制。

我将在class2中使用class1中的on_exit方法。如何正确地解决它？

还有一件事，如何正确创建SettingsWindow？我在下面抛出错误的方式，这表明我错过了争论。

mainWindow = MainWindow（） TypeError： init （）缺少1个必需的位置参数：＆＃39; master＆＃39;

代码：

class MainWindow():

    def __init__(self, master):

        self.master = master

        ...
        some widgets
        ...

    # Trying to create SettingsWindow object
    def open_settings(self):
        settingsWindowsToplevel = Toplevel()
        settingsWindow = SettingsWindow(self, MainWindow)

    # The function i'm gonna use in another class
    def on_exit(self):

        self.master.exit_button()

class SettingsWindow():

    def __init__(self, parent, master):

        self.master = master

        ...
        some widgets again
        ...

# Creating main window
def main():
    root = Tk()
    mainWindow = MainWindow(root)
    root.mainloop()

if __name__ == "__main__":
    main()

我需要从其他课程启动许多功能，而我无法通过tkinter了解如何正确地执行此操作。

感谢。

Answer 1

这不是您正在寻找的解决方案，但我认为考虑好。一切都在一个Tk类中实现，在这种情况下总是只有一个窗口。但是如果有人知道的话，我也希望看到继承的解决方案。

from tkinter import *
from tkinter import ttk


class MainWindow():

    def __init__(self, mainWidget):
        self.main_frame = ttk.Frame(mainWidget, width=300, height=150, padding=(0, 0, 0, 0))
        self.main_frame.grid(row=0, column=0)

        self.some_kind_of_controler = 0

        self.main_gui()

    def main_gui(self):
        root.title('My Window')

        self.main_label_1 = ttk.Label(self.main_frame, text='Object_1')
        self.main_label_1.grid(row=0, column=0)

        self.main_label_2 = ttk.Label(self.main_frame, text='Object_2')
        self.main_label_2.grid(row=1, column=0)

        self.main_label_3 = ttk.Label(self.main_frame, text='Object_3')
        self.main_label_3.grid(row=2, column=0)

        self.setings_button = ttk.Button(self.main_frame, text='Setings')
        self.setings_button.grid(row=0, column=1)
        self.setings_button.bind('<Button-1>', self.setings_gui)

        self.gui_elements = [self.main_label_1,
                             self.main_label_2,
                             self.main_label_3,
                             self.setings_button]

    def setings_gui(self, event):
        self.gui_elements_remove(self.gui_elements)

        root.title('Setings')

        self.main_label_1 = ttk.Label(self.main_frame, text='Object_1')
        self.main_label_1.grid(row=2, column=0)

        self.main_menu_button = ttk.Button(self.main_frame, text='Main menu')
        self.main_menu_button.grid(row=0, column=1)
        self.main_menu_button.bind('<Button-1>', self.back_to_main)

        self.some_kind_of_controler = 1

        self.gui_elements = [self.main_label_1,
                             self.main_menu_button]

    def back_to_main(self, event):
        if self.some_kind_of_controler == 1:
            self.gui_elements_remove(self.gui_elements)
        else:
            pass
        self.main_gui()

    def gui_elements_remove(self, elements):
        for element in elements:
            element.destroy()

def main():
    global root

    root = Tk()
    root.geometry('300x150+50+50')
    window = MainWindow(root)

    root.mainloop()

if __name__ == '__main__':
    main()

Answer 2

通常的做法是将主窗口的引用传递给设置窗口：

class SettingsWindow():
    def __init__(self, parent, master):
        self.master = master
        ...
    def on_exit(self):
        self.master.exit_button()

mainWindow = MainWindow(...)
...
settingsWindow = SettingsWindow(..., mainWindow)

使用Tkinter

2 个答案: