Question

嗨，在用户输入字母而不是数字时捕获实例时遇到问题。获取错误'无法为函数调用指定编号'

这是一个简单的两个QLine编辑框，用户必须猜测数字...任何帮助将不胜感激。刚刚发布了功能位

 def my_response():
        global counter, random_number
        timer=QtCore.QTimer

        try:
            reply.text()= int(reply.text())

            if int(reply.text()) <self. random_number:
                question.setText("Your guess is too low. Please Try Again")
                reply.setText(" ")


            elif int(reply.text()) >self. random_number:
                question.setText("Your guess is too high. Please Try Again")
                reply.setText(" ")


            elif int(reply.text()) ==self. random_number:
                question.setStyleSheet('QLineEdit{color: blue}')
                question.setFont(QtGui.QFont("Stencil", 15, QtGui.QFont.Bold))
                question.setText("Correct")
                timer.singleShot(250,lambda:question.setText('You won'))
                reply.setText(" ")

        except:
            reply.setText('invalad input number is needed')

Answer 1

错误发生在

{{param|BEC}}

信息很简单 - 您无法为电话呼叫分配号码。（实际上，你不能为函数调用分配任何东西。）

另请注意，您可以将reply.text()= int(reply.text())或inputMask分配给QLineEdit，但您根本不必检查无效输入。

pythonQt捕获非整数输入

1 个答案: