获取列值优先的结果

Question

Rails 3.2.8

我有以下内容：

def index
  params[:direction] ||= "desc"
  params[:sort] ||= "status"
  @products = product.solr_search( include: [:customer] ){
    fulltext params[:query] if params[:query].present?
    with :status, (params[:status] || params[:filter]) if (params[:status] || params[:filter]).present?
    order_by( params[:sort], params[:direction] ) if params[:sort].present? && params[:direction].present?
    paginate page: params[:page], per_page: params[:per_page]
  }.results
end

我想做的是在status列='new'时以优先级进行初始排序。在MySQL中，它将是这样的：

SELECT * from product ORDER BY case when status = 'new'

知道我的语法应该是什么吗？